All categories

3 years ago

What is the discriminant of 3х^2 + 6x = 2?

Mathematics

1 answer:

Bezzdna [24]3 years ago

7 0

Answer:

Δ = 60

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c = 0 : a ≠ 0

Then the discriminant

Δ = b² - 4ac

Given

3x² + 6x = 2 ( subtract 2 from both sides )

3x² + 6x - 2 = 0 ← in standard form

with a = 3, b = 6 and c = - 2

b² - 4ac = 6² - (4 × 3 × - 2) = 36 - (- 24) = 36 + 24 = 60

You might be interested in

The expression 3 ( 1 . 5 )^ t models the number of bacteria in a culture as a function of the number of hours since the culture

Masteriza [31]

Answer:

Step-by-step explanation:

Given

3 $(1.5)^{t}$

When the culture was created t = 0, thus

3 $(1.5)^{0}$ = 3 × 1 = 3

That is there were initially 3 bacteria in the culture → A

4 0

3 years ago

I need help with both questions...

NikAS [45]

Answer:

17. a)

Step-by-step explanation:

17.

f(x) =x/2, then f(x-3)=(x-3)/2

x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)

f(x-3)+3=0+3=3

18.

f(x) =x/2

f(x-2) for x=5 is f(5-2)=f(3)=3/2

f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2

3 0

3 years ago

Read 2 more answers

Multiply (6 − 7i)(3 − 6i).

Leviafan [203]

Answer:

-24 - 57i

Step-by-step explanation:

i'm assuming that this is a question about imaginary numbers and that i²= -1

we can expand the binomial by using the FOIL method (see attached)

(6 − 7i)(3 − 6i)

= (6)(3) + (6)(-6i) + (-7i)(3) + (-7i)(-6i)

=18 - 36i - 21i + 42i² (recall that i²= -1)

= 18 - 57i + 42(-1)

= 18 - 57i - 42

= -24 - 57i

5 0

3 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

3 0

3 years ago

Read 2 more answers

Could someone help me solve this

faltersainse [42]

Answer:

x = 8.3.

Step-by-step explanation:

According to solve for the length of x, we need to use SOH CAH TOA.

This means...

Sine: Opposite over Hypotenuse

Cosine: Adjacent over Hypotenuse

Tangent: Opposite over Adjacent

In this case, we are given the angle, the hypotenuse, and we need to solve for the adjacent. This means that we will use cosine, since we have the adjacent and the hypotenuse.

cosine(41) = x / 11

x = (cosine(41)) * 11

x = 0.7547095802 * 11

x = 8.301805382

The question asks us to round to the nearest <em>tenth</em>.

So, your final answer is that x = 8.3.

Hope this helps!

7 0

3 years ago

Read 2 more answers