I believe it becomes kinetic energy, however I’m not entirely sure. I hope it helped though.
Answer:
1.4 mols
4th answer
Explanation:
22. 5 g of O2 in moles = (22.5/32) mols = 0.703 mol
The stoichiometry between O2 and H2O =1: 2
Therefore H2O produced = 2 * 0.703 mols=1.406 mols
Answer:
<u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>
Explanation:
Step 1: What are hydrogen ion donor and acceptor
in the following reaction we see that:
⇒ H2PO4- is more likely to give a H+ ion to form HPO42-.
⇒HPO42- is more likely to take a H+ ion, to form H2PO4-
The reaction of an acid in water solvent is described as a dissociation
:
HA ⇔ H+ + A-
⇒where HA is a proton acid
So, H2PO4- = HA and HPO42- = A-
Acids are proton donors. So, <u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>
Answer:
Answer:
C
Explanation:
Greenhouse gases allow for sunlight, and the heat radiation to enter the atmosphere, and then prevent it from exiting the atmosphere. Known as the greenhouse effect.
Explanation:
As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its 
can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.
Let the three equations with given be denoted as (1), (2), (3), and the last equation (4). Let 
, 
, and 
be letters such that 
. This relationship shall hold for all chemicals involved.
There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, 
shall resemble the number of 
left on the product side when the second equation is directly added to the third. Similarly
Thus
and
Verify this conclusion against a fourth species involved- 
for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.
Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.
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