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PtichkaEL [24]
3 years ago
11

Chlorine has seven electrons in its valence shell. It accepts an electron to complete its octet and becomes a chlorine ion (Cl-)

. What is the nature of this chlorine ion? A. Cation B. Anion C. Metal ion
Chemistry
1 answer:
KIM [24]3 years ago
5 0
The correct answer here is B - when chlorine accepts an electron to complete its octet and becomes a chlorion ion it becomes an Anion. An anion is a negatively charged ion. Chloride ions are an important electrolyte within the body.
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At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---> +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
3 years ago
Compare and contrast the processes of mining coal and extracting oil​
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Answer:

When you mine, you usually drill the oil whereas you mechanically press oil when you extract it.

Explanation:

hope this helped, sry it took so long.

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What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the
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They have general formula as R–OH

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R => is an alkyl group

OH => is the hydroxyl group

The hydroxyl group (OH) is the functional group of the alkanol (alcohol)

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