The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻
CaCl₂ --> Ca²⁺ + 2Cl⁻
the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol
molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L = 0.0375 mol
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750
total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL
concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M
The answer is A - earth shadow cast in moon
Hey there!
Given the reaction:
P4 + 10 Cl2 ------------------ 4 PCl5
Molar mass P4 = 124 g/mol
Number of moles P4:
n = mass of solute / molar mass
n = 24.0 / 124
n = 0.1935 moles of P4
Therefore:
1 mole P4 --------------- 4 moles PCl5
0.1935 moles P4 ------- moles PCl5
moles PCl5 = 0.1935 * 4
= 0.774 moles of PCl5
Hope that helps!
Answer:
A student wrapped in a blanket or siting in the hot sun or showering with hot water
Explanation: