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3 years ago

What is measurement?

Physics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer:

measurement is defined as act of measuring or the size of something

love history [14]3 years ago

4 0

Explanation:

Hey there!!

The process of comparing the unknown quantities with the help of known quantities are called measurement. For example, length is measured in metre, time in second, mass in kilograms and so on to measure quantities.

Hope it helps..

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The energy spacing between levels 1 and 2 is twice that between 2 and 3. If an electron makes a transition from level 3 to level

vovikov84 [41]

Answer: $\lambda _3=\frac{\lambda }{3}$

Explanation:

Given

$E_3-E_2=\frac{hc}{\lambda }$

also $E_2-E_1=2\left ( E_3-E_2\right )$

Let wavelength produce during transition from 2 to 1 is $\lambda_0$

$\frac{hc}{\lambda _0}=2\frac{hc}{\lambda }$

$\lambda _0=\frac{\lambda }{2}$

For $E_3 to E_1 transition$

$E_3-E_1=E_3-E_2+E_2-E_1$

$E_3-E_1=\frac{hc}{\lambda }+2\frac{hc}{\lambda }$

$\frac{hc}{\lambda _3}=3\frac{hc}{\lambda }$

$\lambda _3=\frac{\lambda }{3}$

5 0

3 years ago

A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential

castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge $q=+10.5\times10^{-6}\ C$

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

$\Delta U=-W$

$\Delta U=-F\cdot d$

$\Delta U=-q(E\cdot d)$

Put the value into the formula

$\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}$

$\Delta U=-3.32\times10^{-3}\ J$

The change in electric potential energy is $-3.32\times10^{-3}\ J$

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

$\Delta U=-W$

$\Delta U=-F\cdot (-d)$

$\Delta U=-q(E\cdot (-d))$

Put the value into the formula

$\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})$

$\Delta U=3.32\times10^{-3}\ J$

The change in electric potential energy is $3.32\times10^{-3}\ J$

Hence, This is the required solution.

3 0

4 years ago

Mollie is using springs to hang art projects. She hang a 3.0kg picture on one particular spring and it stretches from 30 cm to 4

fgiga [73]

Spring constant, k = 784 N/m

Distance = 49 cm

Explanation:

Given:

Mass, m₁ = 3 kg

Distance, x₁ = 30 cm

Distance, x₂ = 45 cm

Spring constant, k = ?

(a)

When the mass is being stretched at a height then potential energy gets converted to kinetic energy.

Potential energy = kinetic energy

$mgh = \frac{1}{2} k(h-x)^2$

On substituting the value, we get:

$3 X 9.8 X 0.3 = \frac{1}{2} X k X (0.45 - 0.3)^2\\ \\8.82 = \frac{1}{2} X k X (0.15)^2\\ \\17.64 = k X 0.0225\\\\k = \frac{17.64}{0.0225}\\ \\k = 784 N/m$