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3 years ago

Provide any THREE types of financiei esitance that can be for

Physics

1 answer:

spayn [35]3 years ago

8 0

Answer:

University Need-Based Scholarships.

Federal and State Grants and Scholarships.

Loan Assistance.

Academic Year Student Contribution: AYSC.

Student Employment.

Outside Scholarships.

doing tutors for class 5 below

working as a waitree

and doing small business

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A ball dropped from a window strikes the ground 2.76 seconds later. How high is the window above the ground

sweet [91]

Answer:

37.33m

Explanation:

Using the equation of motion

S = ut + 1/2gt^2

Time t = 2.76secs

g = 9.8m/s^2

S = 0 + 1/2(9.8)(2.76)^2

S = 4.9*7.6176

S = 37.33

Hence the window is 37.33m above the ground

7 0

3 years ago

suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be

d1i1m1o1n [39]

Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 <span>candela</span>

7 0

3 years ago

What is the momentum of a 1, 500 kg car traveling at 3m/s?

ruslelena [56]

4,500 kgm/s bc 1,500x3

6 0

3 years ago

Read 2 more answers

What force is needed to move a barrel 45-m if 3600 J of work are accomplished?

lesantik [10]

Answer:

<h3>The answer is 80 N</h3>

Explanation:

The force acting on the object can be found by using the formula

$f = \frac{w}{d} \\$

where

d is the distance

w is the work done

We have

$f = \frac{3600}{45} \\$

We have the final answer as

Hope this helps you

8 0

3 years ago

Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ

Sergio039 [100]

Answer:

$\lambda_{B}=414.67 nm$

Explanation:

In this question we have given

$\lambda_{A}=622nm$

we have to find

$\lambda_{B}=?$

We know that

optical path difference for bright fringe is given as $=n\lambda$

Here,

n is order of fringe

and optical path difference for dark fringe is given as $=(n+.5)\lambda$

since the light with wavelength $\lambda_{A}$ produces its third-order bright fringe at the same place where the light with wavelength $\lambda_{B}$ produces its fourth dark fringe