Which of the following correctly describes the relationship between current and voltage as the voltage of a battery increases. R
1 answer:
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Refer to the diagram shown below.
The given data is
mass, kg Coordinates. m
------------- -----------------
2 (0, 0)
2 (2, 0)
4 (2, 1)
Total mass, M = 2+2+4 = 8kg
Let (x,y) be the coordinates of M.
Then, taking moments about the origin, we obtain
8x = 2*0 + 2*2 + 4*2 = 12
x = 1.5 m
8y = 2*0 + 2*0 + 4*1 = 4
y = 0.5 m
Answer: (1.5, 0.5) m
The given data is
mass, kg Coordinates. m
------------- -----------------
2 (0, 0)
2 (2, 0)
4 (2, 1)
Total mass, M = 2+2+4 = 8kg
Let (x,y) be the coordinates of M.
Then, taking moments about the origin, we obtain
8x = 2*0 + 2*2 + 4*2 = 12
x = 1.5 m
8y = 2*0 + 2*0 + 4*1 = 4
y = 0.5 m
Answer: (1.5, 0.5) m
Answer:
a)
b)
c)
Explanation:
a) The speed of a wave is given by the following equation:
Where:
λ is the wavelength
f is the frequency
b) The harmonic wave has the following equation:
A is the amplitude (2 m)
k is the wavenumber (2π/λ)
ω is the angular frequency (2πf)
c) Here we need to find the heigth at x=3 m and t =10 s, so we need to find y(3,10).
I hope it helps you!
We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.
We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.
The following equation has everything we need:
So plug in the known values and solve for a:
0 = 24 + 6a
-24 = 6a
a = -4 m/s^2
We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.
The following equation has everything we need:
So plug in the known values and solve for a:
0 = 24 + 6a
-24 = 6a
a = -4 m/s^2
F = Magnetic Force
B = Magnetic Field
V = Velocity
*The vectors from the photo you get doing the left-hand rule.
The magnetic force is always perpendicular to the magnetic field.
And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.
The formula to find the Magnetic Force is:
Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.
Newton (N) = C x m/s x T = (C x m x T)/s
B = Magnetic Field
V = Velocity
*The vectors from the photo you get doing the left-hand rule.
The magnetic force is always perpendicular to the magnetic field.
And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.
The formula to find the Magnetic Force is:
Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.
Newton (N) = C x m/s x T = (C x m x T)/s