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Nezavi [6.7K]
3 years ago
12

What is evaporation? Condensation? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.

ResetHelp liquid gaseous solid Evaporation is the physical change in which a substance converts from its state to its state. Condensation is the physical change in which a substance converts from its state to its state.
Physics
1 answer:
krok68 [10]3 years ago
7 0

Answer:

Evaporation is the physical change in which a substance converts from its <u>liquid</u> state to its <u>gaseous</u> state. Condensation is the physical change in which a substance converts from its <u>gaseous</u> state to its <u>liquid</u> state.

Explanation:

Evaporation and condensation are opposite processes to each other. Evaporation changes a liquid to a gas and condensation is the reverse.

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Determine the speed of the 50-kg cylinder after it has descended a distance of 2 m, starting from rest. Gear A has a mass of 10
Naddika [18.5K]

This question is incomplete, the missing image is uploaded along this answer below.

Answer:

the speed of the 50-kg cylinder after it has descended is 3.67 m/s

Explanation:

 Given the data in the question and the image below;

relation between velocity of cylinder and velocity of the drum is;

V_D = ω_c × r_c  ----- let this be equ 1

where V_D is velocity of cylinder,  ω_c is the angular velocity of drum C and r_c is the radius of drum C

Now, Angular velocity of gear B is;

ω_B = ω_C

ω_B = V_D / r_c  -------- let this equ 2

so;

V_D / 0.1 m = 10V_D

Next, we determine the angular velocity of gear A;

from the diagram;

ω_A( 0.15 m ) = ω_B( 0.2 m )

from equation 2; ω_B = V_D / r_c

so

ω_A( 0.15 m ) = (V_D / r_c ) 0.2 m

substitutive in value of radius r_c (0.1 m)

ω_A( 0.15 m ) = (V_D / 0.1 m ) 0.2 m

ω_A( 0.15 ) = 0.2V_D / 0.1

ω_A =  2V_D  / 0.15

ω_A = 13.333V_D   ----- let this be equation 3

To get the speed of the cylinder, we use energy conversation;

assuming that the final position is;

T₁ + ∑U_{1-2 = T₂

0 + m_Dgh = \frac{1}{2}m_DV²_D + \frac{1}{2}I_Aω²_A + \frac{1}{2}I_Bω²_B

so

m_Dgh = \frac{1}{2}m_DV²_D + \frac{1}{2}(m_Ak_A²)(13.333V_D)² + \frac{1}{2}(m_Bk_B²)(10V_D)²

we given that; m_D = 50 kg, h = 2 m, m_A = 10 kg, k_A 125 mm = 0.125 m, m_B = 30 kg, k_B = 150 mm = 0.15 m.

we know that; g = 9.81 m/s²

so we substitute

50 × 9.81 × 2 = ( \frac{1}{2} × 50 × V_D²) + \frac{1}{2}( 10 × (0.125)² )(13.333V_D)² + \frac{1}{2}( 30 × (0.15)²)(10V_D)²

981 = 25V_D² + 13.888V_D² + 33.75V_D²

981 = 72.638V_D²

V_D² = 981 / 72.638

V_D² = 13.5053

V_D = √13.5053

V_D = 3.674955 ≈ 3.67 m/s

Therefore,  the speed of the 50-kg cylinder after it has descended is 3.67 m/s

7 0
3 years ago
Can a vector have a component greater than its magnitude
galina1969 [7]

Answer:

NO

Explanation:

The components of a vector can not have a magnitude greater than the vector itself.The magnitude of a component is always lesser than vector because the magnitude is a product of the vector and cos Ф where the value of cos Ф , x,  is -1<x<1. Additionally, applying the Pythagorean relationship, you expect the sum of squares of the components to equal the square of the magnitude of the vectors.However, there is a situation where a component of a vector has a magnitude which equals the magnitude of the vector.

6 0
3 years ago
What is the average velocity of a dragster that starts from rest at the starting line and finishes a race at 2600 m/s in 12 seco
xxMikexx [17]
Using the equation v(avg)=distance/time 
and the equation v=v(original)+a(t)
solve for acceleration
2600=0+a(12)
a=216.66666 m/s^2

Then, you use the equation
v^2=v(original)+2a*(change in x)
2600^2=2(216.666666)*change in x
6760000/2/216.666666 = 15600 meters which is the length of the race

Then using v(avg)=x/t
15600/12= 1300 m/s
7 0
3 years ago
Что сделать чтоб предмет облодал магнитными свойствами?​
Brut [27]
What is the question?
4 0
3 years ago
Which energy conversion correctly describes what happens when you are dancing
geniusboy [140]
Kinetic because u are moving around a lot!
6 0
2 years ago
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