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mash [69]
3 years ago
11

How many seismograph stations are needed to locate the epicenter of an earthquake?

Physics
1 answer:
marshall27 [118]3 years ago
3 0

There are three seismograph

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What type of system allows energy but not matter to enter and exit?
Nastasia [14]

Answer:

closed

Explanation:

A closed system allows energy (usually heat) to be exchanged but not matter.

Your welcome

5 0
3 years ago
The second-order bright fringe in a single-slit diffraction pattern is 1.35 mm from the center of the central maximum. The scree
Dafna11 [192]

Answer:

The wavelength is 754.2 nm.

Explanation:

Given that,

Diffraction pattern y= 1.35 mm

Width = 0.838 mm

Distance D= 75 cm

We need to calculate the wavelength

Using formula of diffraction pattern

y=\dfrac{m\lambda D}{d}

\lambda=\dfrac{yd}{mD}

Where, y = diffraction pattern

m = order

d = width

D = distance

Put the value into the formula

\lambda=\dfrac{1.35\times10^{-3}\times0.838\times10^{-3}}{2\times75\times10^{-2}}

\lambda=7.542\times10^{-7}\ m

\lambda=754.2\ nm

Hence, The wavelength is 754.2 nm.

4 0
3 years ago
Which of the following is a graph of the velocity of an object as it falls fromrest if drag is not ignored? Explain your choice
MariettaO [177]

The air drag is a force that depends on the speed of an object relative to the wind. Under certain conditions, it can be modeled as:

F=-bv

Where b is a constant.

As a falling object reaches a speed so that its weight is cancelled out by the air drag, the object will reach a maximum velocity.

In a speed vs time gaph, the speed would approach the maximum speed like an asymptote.

On the other hand, since the object falls from rest, the initial speed on the graph must be zero.

Taking these considerations into account, the correct graph for the movement of an object that falls from rest if air drag is not ignored, is option B.

7 0
1 year ago
A soccer player attempting to steal the ball from an opponent was extending her knee at 50 deg/s when her foot struck the oppone
denpristay [2]

Answer:

\alpha = -4.36 rad/s^2

Explanation:

Initial angular speed of the player is given as

\omega = 50 deg/s

here we know that

1 deg = \frac{\pi}{180} rad

now we know that

\omega = 50\frac{\pi}{180}

\omega = 0.87 rad/s

now its speed comes to zero in 0.2 s

so angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0 - 0.87 rad/s}{0.2 s}

\alpha = -4.36 rad/s^2

7 0
3 years ago
2 QUESTIONS HELP PLZ...:/
algol [13]
The first one is: head
Second one is: 10 trillion km
5 0
4 years ago
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