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4 years ago

Mike, who has 6 video games, has half as many games as Paul.

2 answers:

4 0

It's pretty easy, it means that Paul has twice as many games as Mike has. But mathematically we can write it down as:

6 = 1/2 x / * 2 (both sides)
x = 12

I hope it helped :)

8_murik_8 [283]4 years ago

3 0

If Mike has half as many as Paul, then Paul has twice as many as Mike.

Mike = Paul/2 so 6 = Paul/2
Multiply both sides by 2
12 = Paul

or
Paul = Mikex2
Paul = 6x2
Paul = 12

Hope that helps

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A leprechaun places a magic penny under a girl's pillow. The next night there are 2 magic pennies under her pillow. The followi

vfiekz [6]

Answer:

Step-by-step explanation:

Since the pennies need to be kept under the pillow in order to be doubled, we're really looking for the day the girl will wake up with 5 billion pennies under her pillow.

The general formula of that geometric sequence will be: t = 1 + 2^(n-1)

We need to find the value of n when t will be over 5,000,000,000.

So, the equation becomes:

5,000,000,001 = 1 + 2^(n-1)

$2^{n-1}= 5,000,000,001$

$log(2^{n-1}) = log(5,000,000,000)$

(n-1) * log(2) = log(5,000,000,000)

n-1 = log(5,000,000,000) / log(2)

n-1 = 22.25

n = 33.25

Since it has to be complete days, and we have to reach over 5 billion, then we round it up to 34.

7 0

3 years ago

0.4 is 10 times as much as ?

dimulka [17.4K]

0.4 is 10 times as much as ? for answering this, we put x an unknown number such that 0.4 is 10 times as much as x, so it does mean 0.4 =10x, so for finding the value of x, we divids 0.4 by 10, x= 0.4/10=0.04. the answer is 0.4 is 10 times as much as 0.04Hope this helps. Let me know if you need additional help!

8 0

3 years ago

Read 2 more answers

Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

Eric tossed two coins in the air at the same time. He recorded the results of each toss. He tossed the coins 100 times. About ho

Anna007 [38]

Answer:

25 times

Step-by-step explanation:

p(HT) p(hh) p(tt) p(HT)

h-heads

t-tails

p(hh)=(1/4*100)

6 0

3 years ago

A cactus casts a shadow 33 feet long. At the same time of day, Liam who is 6 feet tall, casts a shadow 9 feet long, as shown.

castortr0y [4]

Answer:

here's the solution :-

1.) =》the base of the larger triangle is the length of shadow formed by cactus .

so, length of cactus is : 33 feet.

2.) now, jn the smaller triangle formed by liam and it's shadow : -

=》

since both triangle form 90° the bases of both the larger and smaller triangles are parallel , so the base angles of larger triangle = corresponding base angles of the smaller triangle

hence, the both triangles are similar

( by A.A postulate )

now since the both triangles are similar, the the sides will be proportional ,

=》

$\frac{9}{33} = \frac{6}{x}$