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RUDIKE [14]
3 years ago
14

If a horse is running at a speed of 35 m/s when it's rider pulls up on the reigns. After 5 seconds the horse slows down to a pac

e of 15 m/s. What is the horse's rate of acceleration?
Physics
2 answers:
Nataliya [291]3 years ago
7 0
The answer is simply 5.51
KonstantinChe [14]3 years ago
6 0
Your answer will be 5.51
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Effects of the earths orbit around the sun
makvit [3.9K]
<h3><u>Effects of the earths orbit around the sun:</u></h3>

The earth moves around the sun in an elliptical orbit, Johannes Kepler, a "German mathematician, and astronomer" described this elliptical orbit first. The orbit is close to being a circle but not a circle. Earth orbiting the sun mainly effects on seasons on earth.

Earth's four seasons are determined when Earth is tilted 23.4 degrees on the vertical axis, which is called as “axial tilt”. When a "southern hemisphere is tilted towards the sun", it experiences summer and northern hemisphere experiences winter, exactly opposite happens when northern hemisphere tilts towards Sun and this climate change goes on in all countries.

7 0
3 years ago
Using a horizontal force of 200 n, we intend to move a wooden cabinet across a floor at a constant velocity. What is the frictio
grin007 [14]

By using the second law of Newton, the frictional force is 200N.

We need to know about the second law of Newton (force) to solve this problem. The total force applied an object is proportional to the mass of object and acceleration. It can be defined as

∑F = m . a

where F is force, m is mass and a is acceleration.

From the question above, we know that

F1 = 200N

v = constant therefore (a = 0 m/s²)

By using second law of Newton, we get

∑F = m . a

F1 - Ffriction = m . 0

200 - Ffriction = 0

Ffriction = 200 N

Hence, the frictional force is 200N.

Find more on force at: brainly.com/question/25239010

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5 0
1 year ago
How much work will a machine with a power rating of 1.1 × 103 watts do in 2.0 hours?
lyudmila [28]

Answer:

D.

Explanation:

8.1X10 to the power of 6 Joules.

7 0
3 years ago
Read 2 more answers
A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with
MAVERICK [17]
The second object, the one that had twice the force applied to it, would move twice as far, I believe.
3 0
3 years ago
A spring with a spring constant of 1200 N/m has a 55-g ball at its end. The energy of the system is 5.5J. What is the amplitude
Pepsi [2]
The energy of the system is E=5.5 J. This energy is the  same at every moment of the oscillation. When the stretch x of the spring is maximum (so, when the stretch is equal to the amplitude: x=A) the velocity of the spring is zero, so all this energy is just elastic potential energy of the spring:
E= \frac{1}{2}kA^2
From which we find
A= \sqrt{ \frac{2E}{k} }= \sqrt{ \frac{2 \cdot 5.5 J}{1200 N/m} }=0.096 m
4 0
3 years ago
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