Duracell batteries are an example of an electrochemical cell that is powered between the reaction of Magnesium and Zinc, occurring in basic conditions (alkaline battery). This type of reaction has a precise output of 1.5 volts, and looks like this:
Zn + 2MnO2 ➡️ ZnO + Mn2O3
It’s not rechargeable.
Golf Cart Batteries are an example of an electrochemical cell that is powered by the reaction between Lead and Sulfuric Acid (Lead-Acid battery). This type of reaction occurs on larger scales than an alkaline battery, and thus can generate a variety of powers depending on how many instruments are present within the battery. The reaction looks like this:
PbO2 + Pb + 2H2SO4 ➡️ 2PbSO4 + H2O
This is a rechargeable cell, but is rather prone to discharging by the environment and surroundings of the battery.
Answer: 200 N/m
Explanation:
The Gravitational spring energy(Us) is equal to 1/2kx^2. So we have x as .2 m and Us as 4 N. So 4 N = 1/2 * k * .2^2. So now we solve for K and get 200 N/m.
Explanation:
It is given that,
Mass of the tackler, m₁ = 120 kg
Velocity of tackler, u₁ = 3 m/s
Mass, m₂ = 91 kg
Velocity, u₂ = -7.5 m/s
We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,


v = -1.5 m/s
Hence, their mutual velocity after the collision is 1.5 m/s and it is moving in the same direction as the halfback was moving initially. Hence, this is the required solution.
The approximate speed of the sound wave traveling through the solid material is 1012m/s.
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Wavelength, Frequency and Speed</h3>
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
From the wavelength, frequency and speed relation,
λ = v ÷ f
Where λ is wavelength, v is velocity/speed and f is frequency.
Given the data in the question;
- Frequency of sound wave f = 440Hz = 440s⁻¹
- Wavelength of the wave λ = 2.3m
To determine the approximate speed of the wave, we substitute our given values into the expression above.
λ = v ÷ f
2.3m = v ÷ 440s⁻¹
v = 2.3m × 440s⁻¹
v = 1012ms⁻¹
v = 1012m/s
Therefore, the approximate speed of the sound wave traveling through the solid material is 1012m/s.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701