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3 years ago

14

If a horse is running at a speed of 35 m/s when it's rider pulls up on the reigns. After 5 seconds the horse slows down to a pac

e of 15 m/s. What is the horse's rate of acceleration?

2 answers:

Nataliya [291]3 years ago

7 0

The answer is simply 5.51

KonstantinChe [14]3 years ago

6 0

Your answer will be 5.51

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Assume that the Styrofoam slab and the fur are both initially neutral, and that the slab charged negatively after it is rubbed w

BARSIC [14]

Charging phenomenon is basically transfer of electrons from one system to other. When a system loses the electrons the it becomes positively charged and when a system gains electrons then it will become negatively charged

so here if slab is rub against fur then one of them will lose the electrons while other will gain the electrons and hence one will get negatively charged and other will get positive charge

Here it is given that slab get negatively charged so correct options are

<em>3. Electrons move from the fur to the slab. </em>

<em>6. The fur becomes positive after rubbing the slab. </em>

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3 years ago

What are the effects of noise?

slega [8]

Answer:

Noise making has led to loss on hearing.

Explanation:

Supposing you like engaging in parties because of the noise of the sound system it can cause loss on hearing if continued for long

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3 years ago

Which statement best defines work? A. Work is the time it takes to move an object once acted upon by a force. B. Work occurs whe

BigorU [14]

a. work is the time it takes to move an object once acted upon by a force

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2 years ago

Read 2 more answers

a 1500 kg car accelerates uniformly from rest to 10.0 meters per secound in 3.0 secound .what is the work done on the car in thi

zubka84 [21]

Answer:

The work done on the car is, W = 75,000 J

The power delivered by the engine, P = 25,000 watts

Explanation:

Given,

The mass of the car, m = 1500 Kg

The initial velocity of the car, u = 0

The final velocity of the car, v = 10 m

The time duration of the travel, t = 3 s

Using the first equation of motion

v = u + at

a = (v - u) / t

Substituting the given values in the above equation

a = (10 - 0) / 3

= 3.33 m/s²

Using the second equations of motion

s = ut + 1/2 at²

= 0 + 0.5 x 3.33 x 3²

= 15 m

The force exerted by the car

F = m x a

= 1500 Kg x 3.33 m/s²

= 5000 N

The work done by the car,

W = F x S

= 5000 N x 15 m

= 75,000 J

Hence, the work done on the car is, W = 75,000 J

The power delivered by the engine,

P = W / t

= 75,000 J / 3 s

= 25,000 watts

The power delivered by the engine, P = 25,000 watts

5 0

3 years ago

A 2kg mass is suspended on a rope that wraps around a frictionless pulley attached to the ceiling with a mass of 0.01kg and a ra

worty [1.4K]

Answer:

The torque on the pulley, when the system is motionless is approximately 9.81 N·m

Explanation:

The given parameters are;

The mass of the object = 2 kg

The friction between the rope and the pulley = 0

The mass of the rope, $m_r$ = 0.5 kg

The mass of the pulley, $m_p$ = 0.01 kg

The radius of the pulley, r = 0.25 m

The torque on the pulley, τ = I·α = F × D

The torque on the pulley, when the system is motionless, τ = F × D

Where;

F = The force acting on the pulley rope = The weight of the mass ≈ 2 kg × 9.81 m/s² = 19.62 N

D = The diameter of the pulley = 2×r = 2 × 0.25 m = 0.5 m

Therefore;

τ = 19.62 N × 0.5 m = 9.81 N·m

The torque on the pulley, when the system is motionless, τ ≈ 9.81 N·m.

4 0

2 years ago