Parallel perpendicular or neither y=6x-3 y=-1/6x + 7

if an object is falling on earth at a terminal velocity of 140 km/hr, does that mean that the acceleration is ZERO?

Simora [160]

If he's falling in a straight line and his speed is not changing, that tells you that his acceleration is zero.

And THAT tells you that the forces on him are balanced, the net force acting on him is zero, and his motion is the same as it would be if there were NO force acting on him.

7 0

4 years ago

PLEASE HELP - basic SUVAT stuff

Goryan [66]

Answer:

1. 5 m/s

2. 8 m/s

3. 10 s

4. 3 m/s

Explanation:

1. Average speed = distance / time

s = 20 m / 4 s

s = 5 m/s

2. First, find the time to travel from A to B:

60 m = 10 m/s × t

t = 6 s

Now find the average speed from A to C:

s = 80 m / (6 s + 4 s)

s = 8 m/s

3. If t is the time traveling from C back to B, and the average speed of the whole trip is 5 m/s, then:

5 m/s = 100 m / (6 s + 4 s + t)

t = 10 s

4. Average velocity = displacement / time

v = 60 m / 20 s

v = 3 m/s

6 0

3 years ago

Con los datos recolectados en la clase anterior sobre la altura (13cm) y tiempo (1 s) de salto calcular la velocidad y la distan

goldfiish [28.3K]

Answer:what

Explanation:

7 0

4 years ago

If you have 240.0 mL of water at 25.00 °C and add 100.0 mL of water at 95.00 °C, what is the final temperature of the mixture? U

Rus_ich [418]

Answer: The final temperature of the mixture is 45.6°C

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

When volume is 240.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{240.0mL}\\\\\text{Mass of water}=(1g/mL\times 240.0mL)=240g$

When volume is 100.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{100.0mL}\\\\\text{Mass of water}=(1g/mL\times 100.0mL)=100g$

When two water solutions at different temperature are mixed, the amount of heat released by water present at higher temperature will be equal to the amount of heat absorbed by water present at lower temperature..

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of water solution 1 = 240 g

$m_2$ = mass of water solution 2 = 100 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of water solution 1 = 25°C

$T_2$ = initial temperature of water solution 2 = 95°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

$240\times 4.186\times (T_{final}-25)=-[100\times 4.186\times (T_{final}-95)]\\\\T_{final}=45.6^oC$

Hence, the final temperature of the mixture is 45.6°C

7 0

3 years ago

Read 2 more answers

Water can fall as precipitation, which may include rain, snow, or hail is an observation or inference?

lukranit [14]

THe best answer would be observation because you can see that all 3 are made up of water which you don't need to infer because you have the proof when you look at all 3 different types of precipitation.

I hope this helps you out.

7 0

3 years ago