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Goryan [66]
3 years ago
5

When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is

8x10-17j. what is the strength of the electric field that causes the change in potential energy?
Physics
1 answer:
anygoal [31]3 years ago
7 0
In the field of electromagnetism, when two charged plates that are situated opposite to each other by a certain distance, it forms an energy called the electric field. This energy is due to the difference in potential energy with respect to distance. Thus,

E = V/d

However, the voltage in volts is energy per coulomb. Thus,
V = (8x10-17 J/electron)*(1electron/1.60218x10^-19 C)
V = 499.32 volts

Therefore,

E = 499.32 volts /2.5 m
E = 199.73 N/C

The electric field that caused the change in potential energy is equal to 199.73 Newtons per Coulomb.
You might be interested in
A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

a =  \frac{6000}{500}  =  \frac{60}{5}  = 12 \\

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

8 0
3 years ago
How far does a car go in 30 seconds at a speed of 29 m/s? (The equation for<br> distance is d = st.)
Harrizon [31]

d = speed x time

distance = 29 x 30

distance = 870m

please mark as BRAINLIEST

8 0
2 years ago
The equation for photosynthesis is 6H2O (water) + 6CO2 (carbon dioxide) + Light Energy → C6H12O6 (glucose) + 6O2 (oxygen). When
aleksklad [387]

Answer:

b

Explanation:

bc

8 0
3 years ago
You walk 45 m to the north, then turn 90° to your right and walk another 45 m How far are you from where you originally started?
docker41 [41]
C^2=a^2+b^2
c^2=45^2+45^2
c^2=4050
c=63.64
c=64
The answer is D.
3 0
3 years ago
Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista
antoniya [11.8K]

The initial velocity of the skier is 4.5 m/s

Explanation:

There is only one force acting on the skier in the horizontal direction, and it is the force of friction, whose magnitude is

F_f = -\mu_k mg

where

\mu_k = 0.050 is the coefficient of kinetic friction

m is the mass of the skier

g=9.8 m/s^2 is the acceleration of gravity

The negative sign is due to the fact that the direction of the force of friction is opposite to the direction of motion of the skier.

According to Newton's second law, the net force acting on the skier is equal to the product between his mass and his acceleration, so we can write:

F=ma\\ \rightarrow -\mu_k mg = ma

So, the acceleration of the skier is

a=-\mu_k g

Now we can apply the following suvat equation to find the initial velocity of the skier:

v^2-u^2=2as

where

v = 0 is the final velocity (he comes to a stop)

u is the initial velocity

s = 21 m is the displacement

a is the acceleration

Substituting the equation for the acceleration and solving for u, we find

u=\sqrt{v^2-2as}=\sqrt{-2(-\mu_k g) s}=\sqrt{2(0.050)(9.8)(21)}=4.5 m/s

Learn more about accelerated motion here:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
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