Speed= (frequency) x (wavelength)
= (2 per second) x (5 cm) = <em><u>10 cm/sec .</u></em>
Resistance = (voltage) / (current)
For this piece of wire . . .
Resistance = (61 volts) / (6 Amperes)
Resistance = (61/6) (V/A)
<em>Resistance = (10 and 1/6) ohms</em>
Since you know the voltage and current, the length doesn't matter.
Answer:
The value of acceleration that accomplishes this is 8.61 ft/s² .
Explanation:
Given;
maximum distance to be traveled by the car when the brake is applied, d = 450 ft
initial velocity of the car, u = 60 mph = (1.467 x 60) = 88.02 ft/s
final velocity of the car when it stops, v = 0
Apply the following kinematic equation to solve for the deceleration of the car.
v² = u² + 2as
0 = 88.02² + (2 x 450)a
-900a = 7747.5204
a = -7747.5204 / 900
a = -8.61 ft/s²
|a| = 8.61 ft/s²
Therefore, the value of acceleration that accomplishes this is 8.61 ft/s² .
Answer:
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