Use this formula for an object starting from rest and accelerating:
Distance = (1/2) (acceleration) (time)²
In this problem, the distance is 40 meters, and acceleration is gravity.
So . . .
40 m = (1/2) (9.8 m/s²) (time)²
Divide each side by (4.9 m/s²) :
time² = (40 m) / (4.9 m/s²)
time² = 8.16 sec²
Take the square root of each side :
√(time²) = √(8.16 sec²)
time = 2.86 seconds
Round it to 2.9 sec <em>(choice B)</em>
Answer:7.93 m/s
Explanation:
Given
mass of ball
Mass of hanging ball
Length of string
Maximum angle turned
is the initial velocity of ball 1 and 0 is the initial velocity of ball 2
For Perfectly elastic final velocity of ball 1 and 2 is given by
where and are the velocity of 1 and 2 before collision
thus
By energy conservation on second ball we get
Kinetic energy=Potential Energy
thus
Our weight is greater on the Earth<span> because of its stronger </span>gravity. .... track A? (b<span>) Is the speed gained by ball </span>B<span> going </span>down<span> the extra dip the .... The force of friction between your </span>back<span> foot and the </span>floor pushes<span> you forward. .... (a) Two force </span>pairs<span> act; </span>Earth's pull<span> on the apple (</span>action<span>), and the apple's </span>pull<span> on the ...</span>
Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²