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krek1111 [17]
1 year ago
9

a 1500 kg vehicle is traveling on a curved, icy road. the road is banked at an angle of 10.0 degrees and has a radius of curvatu

re of 400 m. the velocity of the car necessary to travel on the icy road without sliding is .
Physics
1 answer:
Monica [59]1 year ago
5 0

The vehicle speed required to drive on an icy road without sliding is 28.3 m/s.

The weight of the car is m = 1500 kg

The angle at which the road is inclined is θ = 10

The radius of curvature is r = 400m

The expression for the speed of the car required to travel on the road without sliding is V =\sqrt{rgtan}

V =\sqrt{400*9.8*tan10}

V = 28.3 m/s

Velocity is the rate of change in direction of an object in motion measured by a specific time standard and observed from a specific reference point (for example, 60 km/h north). A key idea in kinematics, the branch of classical mechanics that studies the motion of bodies, is velocity.

The definition of velocity requires both its magnitude and its direction, since it is a physical vector quantity. Velocity is a coherently derived unit that is measured in the SI (metric system) as meters per second (m/s or m/s1). Velocity is a scalar absolute value (magnitude) of speed.

Learn more about Velocity here:

brainly.com/question/18084516

#SPJ4

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A solenoidal coil with 25 turns of wire is wound tightly around another coil with 300 turns. The inner solenoid is 25.0 cm long
joja [24]

Answer:

5.65487\times 10^{-8}\ Wb

1.17\times 10^{-5}\ H

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Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

N_1 = Number of turns of coil  = 25

N_2 = Number of turns of coil 2 = 300

\frac{di_2}{dt} = Rate of current increased = 1.75\times 10^3\ A/s

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Magnetic flux is given by

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The average magnetic flux through each turn of the inner solenoid is 5.65487\times 10^{-8}\ Wb

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L=\frac{N_1\phi}{i_1}\\\Rightarrow L=\frac{25\times 5.65487\times 10^{-8}}{0.12}\\\Rightarrow L=1.17\times 10^{-5}\ H

The mutual inductance of the two solenoids is 1.17\times 10^{-5}\ H

Induced emf is given by

V=-L\frac{di_2}{dt}\\\Rightarrow V=-1.17\times 10^{-5}\times 1.75\times 10^3\\\Rightarrow V=-0.020475\ V

The emf induced in the outer solenoid by the changing current in the inner solenoid is -0.020475 V

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Answer:

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