If an has more positive charges than negative charges then It will overall be A.Positive
<span>A gymnast with mass m1 = 43 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 = 115 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam.
1)What is the force the left support exerts on the beam?
2)What is the force the right support exerts on the beam?
3)How much extra mass could the gymnast hold before the beam begins to tip?
Now the gymnast (not holding any additional mass) walks directly above the right support.
4)What is the force the left support exerts on the beam?
5)What is the force the right support exerts on the beam?</span>
To solve this problem, we must always remember that energy
is conserved. In this case, since he is falling down, he has highest potential
energy at the top and zero at bottom. While his kinetic energy is zero at the top
since he started from rest and highest at the bottom. We can also say that Potential
Energy lost is Kinetic Energy gained thus,
- ΔPE = ΔKE --->
one is negative since PE is losing energy
- m g (h2 – h1) = 0.5 m (v2^2 – v1^2)
Where,
m = mass of tarzan (cancel that out)
g = gravitational acceleration
h2 = height at the bottom= 0
h1 = height at top = 22 m
v2 = velocity at the bottom
v1 = velocity at top = 0 (started from rest)
Therefore substituting all values:
- 9.8 (- 22) = 0.5 (v2^2)
v2 = 20.77 m / s (ANSWER)
It doesn't matter what direction she travels, or how far, or whether she uses the same road in both directions.
If she ends up at the same place she started from, then her displacement for the ride is <em>zero</em>.