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harkovskaia [24]
4 years ago
7

What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Sit

e 1)
                 
Physics
1 answer:
uysha [10]4 years ago
5 0
1. The benefits of been assertive include the following:
a. It improve one self image: When you choose to be assertive, you adopt  a self realistic image.
b. It enhance how we understand others: Been assertive helps you to see others in a more realistic context.
c. Promote self awareness and self confidence: Been assertive helps you to develop a greater respect for your own points of view when dealing with issues. 
d. Been assertive is a less stressful way of communicating.

2. The three steps needed to develop assertive communication, include:
a. Learn to 'no' more often: refuse to please everyone and do not behave according to people expectations of you. Be yourself.
b. Your tone must be properly turned when talking: Do not raise your voice or rush a communication. Be calm and cool when talking.
c. Be open to communication: Be willing to discuss issues until a suitable solution is found.
d. Pay attention to non-verbal communication of others: Keep eye contact when communicating and pay attention to other body gestures. 

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Two hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.20 × 10−3 m2
Novosadov [1.4K]

Answer:

The charge flows through a point in the circuit during the change is 0.044 C.

Explanation:

Given that,

Number of turns in the copper wire, N = 200

Area of cross section, A=1.2\times 10^{-3}\ m^2

Resistance of the circuit, R = 118 ohms

If an externally applied uniform longitudinal magnetic filed in the core changes from 1.65 T in one direction to 1.65 T in the opposite direction.

We need to find the charge flows through a point in the circuit during the change. Due to change in magnetic field an emf is induced in it. It is given by :

\epsilon=\dfrac{d\phi}{dt}

Using Ohm's law :

\epsilon=IR

IR=-\dfrac{d\phi}{dt}\\\\I=-\dfrac{1}{R}\dfrac{d\phi}{dt}

Electric current is equal to the rate of change of electric charge. So,

dq=\dfrac{NA(B(0)-B(t))}{R}\\\\dq=\dfrac{200\times 1.2\times 10^{-3}(1.65+1.65)}{18}\\\\dq=0.044\ C

So, the charge flows through a point in the circuit during the change is 0.044 C.

4 0
3 years ago
During an experiment, you take a measurement of 3.5 inches. What is this
raketka [301]
B. 8.89 (hope this helped.)
You can solve by just doing 3.5in * 2.54
4 0
4 years ago
Sorry relized it wasnt a good picxD 4 please WILL MARK BRANLIEST
Andrej [43]
I think Y is the answer to number 4
7 0
4 years ago
_______ was the first person to propose the idea of moving continents as a scientific hypothesis.
yan [13]
The answer is b alfred wegener 


8 0
3 years ago
Read 2 more answers
In your research lab, a very thin, flat piece of glass with refractive index 2.30 and uniform thickness covers the opening of a
trapecia [35]

Answer:

λ₀= 495.88 nm

Explanation:

To analyze this constructive interference interference experiment by reflection, let's look at two important aspects:

* when a ray of light passes from a medium with a lower index, they refact to another medium with a higher index, the reflected ray has a phase difference of pyres

* When a beam penetrates a material medium, the wavelength of the radiation changes according to the refractive index of the material.

       λₙ = λ₀ / n

when we introduce these aspects in the expression of contributory interference, it remains

        2 d sin θ = (m + ½) λ₀ / n

In general, reflection phenomena are measured at an almost normal angle, whereby θ = π/2  and sin θ = 1

        2 d = (m +1/2) λ₀/ n

         2n d = (m + ½) λ₀

Let's apply this expression to our case

         d = (m + ½) λ₀ / 2n

Suppose we measure on the first interference, this is m = 0

         d = ½ λ₀ / 2n

 

let's calculate

         d = ½ 496 10⁻⁹ / (2 2.30)

         d = 53.9 10-9 m  

This is the thickness of the glass, the next wavelength that gives constructive interference is

          λ₀ = 2 n d / (m + ½)

let's calculate

          λ₀ = 2 2.3 5.39 10-8 / (1 + ½)

          λ₀= 4.9588 10-7 m

          λ₀= 495.88 nm

5 0
4 years ago
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