All categories

3 years ago

1. The density of a substance is 4.8 g/mL. What is the volume of a sample that is 19.2 g?

Chemistry

1 answer:

kolezko [41]3 years ago

8 0

Answer:

d= 4.8g/mL

m= 19.2 g

V=m/d

V= 4 mL

You might be interested in

Molecules can be either positively or negatively charged depending upon their elemental arrangement

Nuetrik [128]

They are positively or negatively charged based on their electrical configuration of electrons*
For example an electronic configuration of 2,8,3 would have a negative charge if +3 since it needs to lose 3 electrons to gain the electrical configuration of a noble gas
2,8,1 would have a charge of +1 for the same reason
2,8,6 would be -2 since it is easier to gain 2 electrons that lose 6 electrons

Hope this helped :))

8 0

2 years ago

How many atoms of each element are represented in Sn(CO3)2

Marina86 [1]

Sn=2
C and O=6
Im pretty confident yet I forgot a bit.

3 0

3 years ago

Read 2 more answers

Two or more different elements chemically combine to form compounds.<br><br> True or false

vodomira [7]

Answer:

true

Explanation:

8 0

2 years ago

How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!

RoseWind [281]

<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 250.747 \ mol \ Xe$

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

3 0

2 years ago

An electrochemical cell is powered by the half reactions shown below.

andrezito [222]

Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.

Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V

Adding up the E0's would yield an overall electric cell potential of +0.93 V.

7 0

3 years ago