HCl is an acid, C5H5N is a base, Cl is an acid, and HC5H5N is an acid.
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Explanation:
Monosaccharides are simple carbohydrates that cannot be further hydrolyzed to simpler carbohydrates. They contain between three and six carbon atoms per molecule.
Polysaccharides are complex carbohydrates . They are condensation polymers derived from very long chains of monosaccharide units.
Structurally, polysaccharides are made up of repeating units of monosaccharides.
<em>Answer:</em>
- Organic compounds are those which are derivatives of hydrocarbons. They are classified into following functional groups.
<em>Alkane: </em>
- Alkane are simplest hydrocarbons.
- They have general formula CnH2n+2. These hydrocarbons contain single bond.
- For example ethane , H3C----CH3.
<em>Alkene:</em>
- Alkene are most reactive.
- They have general formula CnH2n.
- These contain double bond in their structure.
- For example , ethene, H2C=CH2
<em>Alkyne:</em>
- These are less less reactive as compare to alkenes.
- They have general formula CnH2n-2.
- They contain triple bonds in their structure.
- For example Acetylene HC≡CH
<em>Alcohol:</em>
Alcohol have functional group OH. They have general formual R---OH, R may be alkyl group.For example Ethanol H3CH2C---OH
<em>Amine:</em>
- Amine contain NH2 F.G.
- They have general formula R---NH2.
- There are three types of amine like primary, secondary and tertiary amine.
- For example H3CH2C---NH2
<em>Aldehyde:</em>
- Aldehydes have CHO F.G .
- They have general formula R--CHO.
- For example H3CH2C---CHO
<em>Ketone:</em>
- Ketones have R--CO--R functional group.
- For example acetone H3C---CO---CH3
<em>Carboxylic acid:</em>
- They functional group COOH.
- Their general formula is R---COOH.
- For example Acetic acid H3C---COOH
Answer:
0.06M
Explanation:
Using the formula as outlined in this question,
C1V1= C2V2
Where;
V1 = initial volume (Litres)
C1 = initial concentration (M)
V2 = final volume (Litres)
C2 = final concentration (M)
According to the information provided on NaOH in this question, V1 = 100mL = 100/1000 = 0.1 L, V2 = 1L, C1 = 0.6M, C2 = ?
C1V1= C2V2
0.6 × 0.1 = C2 × 1
0.06 = C2
C2 = 0.06M
The new concentration of NaOH is 0.06M.
