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3 years ago

What is the frequency of a wave that has a wavelength of 20 cm and a speed of 10 m/s? 0.5 Hz 50 Hz 10 Hz 200 Hz

Physics

2 answers:

daser333 [38]3 years ago

5 0

Answer:

50 Hz

Explanation:

For those who like equations:

Velocity = frequency × wavelength

For those who like a more intuitive explanation:

Frequency represents how many waves can go through a single point in 1 second. If you have a wave traveling 10 meters per second, and for each wave the length is 0.2 meter, then you know that there are 50 waves stacking together to reach a total length of 10 meters. So, in 1 second, 50 waves can pass, and therefore the answer is 50 Hz

Harrizon [31]3 years ago

3 0

Answer:

50Hz

Explanation:

i took the test

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A boy walks from point C to point D which is 50 m apart. Then, he walks back to point C. what is his displacement of his whole j

enyata [817]

Answer: D. 0 m

Explanation:

Concept:

Here, we need to know the concept of displacement.

Displacement is defined to be the change in position of an object.

The difference between displacement and distance is the total movement of an object without any regard to direction, while displacement is the pure change of position.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

STEP ONE: the boy walks from point C to point D (a distance of 50 m)

C ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ D

50 m

STEP TWO: the boy walks from point D to point C (a distance of 50 m)

D ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ ⇒ C

50 m

STEP THREE: find the displacement

The boy started with point C

The boy ended with point C

He did not change his position throughout the journey.

Therefore, his displacement is 0 m.

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago

A disk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. The disk contains 2.5 x 10-

allochka39001 [22]

Answer:

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

$E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))$

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

$E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })$

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 0

3 years ago

5.57 • Stay Dry! You tie a cord to a pail of water and swing the pail in a vertical circle of radius 0.600 m. What minimum speed

Stella [2.4K]

Answer:

The minimum speed of pail is 2.42 m/s.

Explanation:

Given that,

Radius = 0.600 m

We need to calculate the minimum speed of pail

Using centripetal force

$F=\dfrac{mv^2}{r}$

$mg=\dfrac{mv^2}{r}$

$v=\sqrt{gr}$

Where, v = speed

r = radius

g = acceleration due to gravity

Put the value into the formula

$v =\sqrt{0.600\times9.8}$

$v=2.42\ m/s$

Hence, The minimum speed of pail is 2.42 m/s.

8 0

4 years ago

Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsice force

Dmitriy789 [7]

Answer:

Q = 1.095 x 10^-9 C

Let the force experienced by the top piece of tape be F

F = kQ²/r²

r = distance between the two pieces tape = 1.00cm = 1.00 x 10^ -2 m

1/4(pi)*Eo = k = 8.99 x 10^9 Nm²/C²

The electric force of repulsion between the two charges and the weight of the top piece of tape are equal so

F = kQ²/r² = mg

Where m is the mass of the top piece of tape and g is the acceleration due to gravity

On re-arranging the equation above,

Q² = mgr²/k

Q² = ((11.0 x 10^-6) x 9.8 x (1.00x10^-2)²)/(8.99 x 10^9)

Q = 1.095x10^-9 C

Explanation:

The charge Q on both pieces of tape are equal and both act with a force of repulsion on each other.

The force of repulsion between both tapes pushes the top piece of tape upwards. The weight of the top piece of tape acts vertically downward. Since the top tape is in a position of equilibrium, the two forces acting on the top piece of tape must be equal to each other. This assumption is backed up by newton's first law of motion which states that the summation of all forces acting on a body at rest must be equal to zero. That is

Fe (electric force) - Fg (gravitational force) = 0

Fe = Fg

kQ²/r² = mg

On substituting the respective values for all variables except Q and rearranging the equation Q = 1.09 x 10^-9

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vfiekz [6]

Sweet, Hold On I just need to download le app

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3 years ago