Question

The magnetic force exerted on a 1.2-m segment of straight wire is 1.6 N. The wire carries a current of 3.0 A in a region with a constant magnetic field of 0.50 T. What is the angle between the wire and the magnetic field

Answer 1

Answer:

The angle between the wire and the magnetic field is 62.74⁰

Explanation:

Given;

length of the wire, L = 1.2 m

force exerted on the wire, F = 1.6 N

current carried by the wire, I = 3.0 A

magnetic field strength, B = 0.5 T

The magnitude of a magnetic force on a current-carrying conductor is given as;

F = BIL(sinθ)

$sin(\theta) = \frac{F}{BIL} = \frac{1.6}{0.5 \times 3 \times 1.2} = 0.8889 \\\\sin(\theta) =0.8889\\\\\theta = sin^{-1} (0.8889)\\\\\theta = 62.74^0$

Therefore, the angle between the wire and the magnetic field is 62.74⁰