Answer:
(a) x₁= 0.004 444; (b) y₁ = -0.9545; (c) x₂ = 0.001 905; (d) y₂ = -0.4541;
(e) rise = 0.5004; (f) run = -0.002 539; (g) slope = -197.1; (h) Eₐ = -1.64 kJ·mol⁻¹
Explanation:
This is an example of the Arrhenius equation:
Thus, if you plot ln k vs 1/T, you should get a straight line with slope = -Eₐ/R and a y-intercept = lnA
(a) x₁
x₁= 1/T₁ = 1/225 = 0.004 444
(b) y₁
y₁ = ln(k₁) = ln0.385 = -0.9545
(c) x₂
x₂= 1/T₂ = 1/525 = 0.001 905
(d) y₂
y₂ = ln(k₂) = ln0.635 = -0.4541
(e) Rise
Δy = y₂ - y₁ = -0.4541 - (-0.9545) = -0.4541 + 0.9545 = 0.5004
(f) Run
Δx = x₂ - x₁ = 0.001 905 - 0.004 444 = -0.002 539
(g) Slope
Δy/Δx = 0.5004/(-0.002 539) K⁻¹ = -197.1
(h) Activation energy
Slope = -Eₐ/R
Eₐ = -R × slope = -8.314 J·K⁻¹mol⁻¹ × (-197.1 K⁻¹) = 1638 J/mol = 1.64 kJ/mol
The moles of butane gas and oxygen gas reacted if 2.50 moles of H2O is produced is calculated as below
the equation for reaction
2C4H10 +13 O2 = 8CO2 +10 H2O
the moles of butane (C4H10) reacted calculation
by use of mole ratio between C4H10: H2O which is 2 : 10 the moles of C4H10= 2.50 x2/10 = 0.5 moles of C4H10 reacted
The moles of O2 reacted calculation
by use of mole ratio between O2 : H2O which is 13:10 the moles of O2
= 2.50 x 13/10= 3.25 moles of O2 reacted
Answer:
Organisms
Step-by-step explanation:
Properties of Life. All living organisms share several key characteristics or functions: order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.
Answer:
<h2>251 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 0.251 × 1000
We have the final answer as
<h3>251 g</h3>
Hope this helps you
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point
elevation is directly proportional to the molality of the solution
according to the equation: ΔTb = Kb · b.<span>
ΔTb - the boiling point
elevation.
Kb - the ebullioscopic
constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
