Electrons always fill orbitals in the same order. Each s orbital holds 2 electrons, each set of p orbitals holds 6 electrons, ea
ch set of d orbitals holds 10 electrons, and each set of f orbitals holds 14 electrons. The order in which orbitals are filled, from first to last, is:
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p
To what element does the following electron configuration correspond?
1s22s22p4
A. aluminum: 13 electrons
B. oxygen: 8 electrons
C. boron: 5 electrons
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p
To what element does the following electron configuration correspond?
1s22s22p4
A. aluminum: 13 electrons
B. oxygen: 8 electrons
C. boron: 5 electrons
2 answers:
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Answer : The concentration of NOBr after 95 s is, 0.013 M
Explanation :
The integrated rate law equation for second order reaction follows:
where,
k = rate constant =
t = time taken = 95 s
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.86 M
Now put all the given values in above equation, we get:
[A] = 0.013 M
Hence, the concentration of NOBr after 95 s is, 0.013 M
Answer:
The atom economy of ethane in this process is 19.72 %.
What is atom economy?
The conversion efficiency of a chemical reaction in terms of all the atoms involved and the desired products produced is known as atom economy (atom efficiency/percentage).
Explanation:
C₁₀H₂₂ → C₈H₁₈ + C₂H₄
Molecular weight of C₁₀H₂₂ = 142.28
Molecular weight of C₈H₁₈ = 114.228
Molecular weight of C₂H₄ = 28.053
% Atom economy =
=
= 19.716 %
≈ 19.72 %
To know more about atom economy, click on the link
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