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iogann1982 [59]
3 years ago
14

A piece of copper with a mass of 218 g has a heat capacity of 83.9 j/°c. what is the specific heat of copper?

Chemistry
1 answer:
kari74 [83]3 years ago
4 0
The answer to this question would be: 0.385  j/g°c

Specific heat is the amount of energy needed to increase 1 degree of celcius per one gram of a specific mass. In this question, it needs 83.9 j/°c energy to increase the temperature of 218 g copper. Then, the specific heat would be:  (83.9 j/°c) / 218g= 0.38486  j/g°c
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The name of the covalent compound CCl4 is 'Carbon tetrachloride'.

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For your 13th answer in #4, what is the other name for this particle?
solong [7]

Answer:

The First layer is the troposphere. The troposphere is what we live in. It creates weather for us. Second layer is the Stratosphere. You will find the ozone layer in it. The ozone layer helps protect us from ultraviolet radiation (UV) from the sun. In fact, the ozone layer absorbs most of the UV radiation the sun sends to us. Life as we know it wouldn't be possible without this layer of protection. Third layer is Mesosphere. The Mesosphere is very important for earth's protection. The mesosphere burns up most meteors and asteroids before they are able to reach the earth's surface. Fourth layer is Thermosphere. The Thermosphere absorbs the sun radiation making it very hot.

Explanation: I don't know if you include this one but the fifth layer is the Exosphere. Although the exosphere is the most distance layer of earth's atmosphere it is the layer that is the planet's first line of defense against the sun's rays. It is also the first layer to come into contact and protect the earth from meteors, asteroids, and cosmic rays.

8 0
2 years ago
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The diagram below shows a longitudinal wave at one instant in its motion. Each oval represents a particle acted on by the ener t
Anton [14]

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the first line

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8 0
3 years ago
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Why bromine is a ring deactivator as it is ortho-Para directing group??
Anettt [7]

Answer:

here you go

Explanation:

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7 0
3 years ago
Determine the concentrations of mgcl2, mg2 , and cl– in a solution prepared by dissolving 2.75 × 10–4 g mgcl2 in 1.75 l of water
inysia [295]

Answer:


M of MgCl₂ = 1.65 × 10⁻⁶ M


M of Mg²⁺ = 1.65 × 10⁻⁶ M


M of Cl⁻ = 3.30 × 10⁻⁶ M



Explanation:



1) MgCl₂


Molarity = number of moles of solute / volume of solution in liters, M = n / V


n = mass in grams / molar mass


molar mass of MgCl₂ = 24.305 g/mol + 2(35.543 g/mol) = 95.211 g/mol


n = 2.75 × 10⁻⁴ g / 95.211 g/mol = 2.89×10⁻³ moles


⇒ M = n / V = 2.89×10⁻³ moles / 1.75 l = 1.65 × 10⁻⁶ M



2) Mg²⁺ and Cl⁻


Those are the ions in solution.


You assume 100% dissociation of the ionic compound (strong electrolyte).


Then the equation is: MgCl₂ → Mg²⁺ + 2Cl⁻


That means that 1 mol of MgCl₂ produces 1 mol of Mg²⁺ and 2 moles of Cl⁻.


That yields the same molarity concentration of Mg²⁺ , while the molarity concentration of Cl⁻ is the double.



So, the results are:


M of MgCl₂ = 1.65 × 10⁻⁶ M


M of Mg²⁺ = 1.65 × 10⁻⁶ M


M of Cl⁻ = 3.30 × 10⁻⁶ M

8 0
2 years ago
Read 2 more answers
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