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iogann1982 [59]
3 years ago
14

A piece of copper with a mass of 218 g has a heat capacity of 83.9 j/°c. what is the specific heat of copper?

Chemistry
1 answer:
kari74 [83]3 years ago
4 0
The answer to this question would be: 0.385  j/g°c

Specific heat is the amount of energy needed to increase 1 degree of celcius per one gram of a specific mass. In this question, it needs 83.9 j/°c energy to increase the temperature of 218 g copper. Then, the specific heat would be:  (83.9 j/°c) / 218g= 0.38486  j/g°c
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Write the balanced chemical equation for the reaction between aqueous sodium carbonate and
ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

7 0
3 years ago
Explain the reaction of non-metals with oxygen
Ray Of Light [21]
Non-metals and oxygen produce non-metal oxides. Such as sulphur dioxide and nitrogen oxide which are responsible for acidic rain. Hope this helps
3 0
2 years ago
Which of the following has the greatest mass, in grams?1) 1 atom of gold (Au) 2) 1.0 mol mercury (Hg) atoms 3) 2.0 mole of chlor
vlada-n [284]

c is the answer for ur question

3 0
3 years ago
How many milligrams of AgNO3 is required to completely react with 81.5 mg LiOH?
BartSMP [9]

Answer:

m_{AgNO_3}=577.6mg

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:

n_{LiOH}=81.5mg*\frac{1g}{1000mg}*\frac{1mol}{23.95g}  =0.0034molLiOH

Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:

m_{ AgNO_3}=0.0034molLiOH*\frac{1molAgNO_3}{1molLiOH} *\frac{169.87gAgNO_3}{1molAgNO_3} *\frac{1000gAgNO_3}{1gAgNO_3} \\\\m_{AgNO_3}=577.6mg

Best regards!

7 0
2 years ago
4. Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H20(1) Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 10.
slava [35]

Answer:

Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over

Explanation:

For the reaction:

Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)

10,0g of Al₂O₃ are:

10,0g ₓ\frac{1mol}{102g} = <em>0,0980 moles</em>

And 10,0g of HCl are:

10,0 gₓ\frac{1mol}{36,5g} = <em>0,274 moles</em>

<em />

For a total reaction of 0,274 moles of HCl you need:

0,274×\frac{1molesAl_{2}O_3}{6 mole HCl} = <em>0,0457 moles of Al₂O₃</em>

Thus, limiting reactant is HCl

The grams produced of AlCl₃ are:

0,274 moles HCl ×\frac{2 moles AlCl_{3}}{6 moles HCl} × 133\frac{g}{mol} = <em>12,1 g of AlCl₃</em>

<em />

The moles of Al₂O₃ that don't react are:

0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles

And its mass is:

0,0523 molesₓ\frac{102g}{1mol} = <em>5,33 g of Al₂O₃ </em>

<em />

I hope it helps!

7 0
3 years ago
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