Answer:
K = [H2] [CO] / [HCHO]
Explanation:
HCHO(g) ⇌ H2(g) + CO(g)
We can obtain the expression for the equilibrium constant for the above equation as follow:
Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.
Thus, the equilibrium constant, K for the above equation can be written as follow:
K = [H2] [CO] / [HCHO]
Answer:
Major product ethoxide ion
Explanation:
- Sodium hydride acts as a strong base towards ethanol.
- Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
- It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
- Structure of major organic product i.e. ethoxide ion has been shown below.
<h3>
Answer: CO2</h3>
Explanation:
Well C2H6 there are 2 carbon and 6 hydrogen atoms
and having no number on the right of the letter means there is only one atom
Answer:
0.43×10²³ atoms
Explanation:
Given data:
Mass of LiBrO₂ = 4.28 g
Number of atoms of oxygen = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 4.28 g/ 118.84 g/mol
Number of moles = 0.036 mol
We can see 1 mole of LiBrO₂ contain 2 mole of oxygen atm.
0.036 mol × 2 = 0.072 mol
1 mole contain 6.022×10²³ atoms
0.072 mol × 6.022×10²³ atoms / 1mol
0.43×10²³ atoms
