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Kamila [148]
3 years ago
8

The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.

Chemistry
1 answer:
ASHA 777 [7]3 years ago
7 0
We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:

PV = nRT
(672) (1/760) (36.52) = n (0.08206) ( 68 +273.15)
n = 1.15 mol of gas

Hope this answers the question. Have a nice day.
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Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda
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Answer:

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Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}

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Chemical formula LiF.

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Oxygen gain two valence electron to form anion with stable electron configuration as noble gas neon (atomic number 10).

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Ionic charges cation Al³⁺ and anion Cl⁻.

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The right name for AlCl₃ is aluminium chloride.

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