The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.

1 answer:

7 0

We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:

PV = nRT
(672) (1/760) (36.52) = n (0.08206) ( 68 +273.15)
n = 1.15 mol of gas

Hope this answers the question. Have a nice day.

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