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solong [7]
3 years ago
14

Glycerol boils at a higher temperature than water. What does this indicate about the attractive forces of glycerol?

Chemistry
2 answers:
Ilya [14]3 years ago
7 0

The chemical formula for glycerol is HOCH2-CH(OH)-CH2OH while that of water is H-OH. The intermolecular forces in both water and glycerol are the strong H-bonds. However, since there are 3 OH groups/ glycerol molecule vs the one -OH group in water enables glycerol to form more H-bonds when compared to water.

The stronger attractive forces in glycerol causes an increase in its boiling point.

klio [65]3 years ago
6 0

Answer: Glycerol has more attractive forces as compared to water.

Explanation:

Boiling point is the temperature at which vapor pressure of the liquid becomes equal to atmospheric pressure.

Boiling point depends on the strength of inter molecular forces.

The molecules of glycerol (HOCH_2CH(OH)CH_2OH) are more strongly bonded through hydrogen bonds as there are three OH groups.

But in water (H_2O) , only on e OH group is present and thus extent of hydrogen bonding is less.

Thus we can conclude that glycerol has more attractive forces as compared to water.

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Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
`What would be the proper way to write the formula for an ionic compound containing carbon and oxygen?
harina [27]
D because Carbon and Oxygen form covalent compounds. I wasn't the greatest at chem., but I'm pretty sure this is correct :D let me know if I gave you the right answer.
6 0
3 years ago
Which process is expected to have an increase in entropy?
olganol [36]

Answer: Option (B) is the correct answer.

Explanation:

Degree of randomness of the molecules of a substance is known as entropy. More is the kinetic energy between the molecules of a substance more will be the degree of randomness.

Therefore, when a substance is present in a gaseous state then it has the maximum entropy. In liquid state, molecules are closer to each other so, there is less randomness between them.

On the other hand, in solid state molecules are much more closer to each other as they arr held by strong intermolecular forces of attraction. Therefore, they have very less entropy.

  • When liquid water is formed from gaseous hydrogen and oxygen molecules then gas is changing into liquid. So, there is decrease in entropy.
  • When N_{2}O_{4} decomposes then the reaction will be as follows.

            N_{2}O_{4} \rightarrow 2NO_{2}

Since, 1 mole is producing 2 moles. This means that degree of randomness is increasing as both the molecules are present in gaseous form.

  • In formation of a precipitate, aqueous solution is changing into solid state. Hence, degree of randomness is decreasing.
  • Rusting of iron also leads to the formation of solid as it forms Fe_{2}O_{3}.xH_{2}O.

Thus, we can conclude that decomposition of N_{2}O_{4} gas to NO_{2} gas is the process that is expected to have an increase in entropy.

4 0
3 years ago
How many atoms are in NH4Cl.
RSB [31]

Answer:

there are 6

Explanation:

3 0
3 years ago
What happens to an acid when it dissolves in water?
shusha [124]
The concentration of the acid decreases
5 0
3 years ago
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