All categories

3 years ago

Glycerol boils at a higher temperature than water. What does this indicate about the attractive forces of glycerol?

2 answers:

7 0

The chemical formula for glycerol is HOCH2-CH(OH)-CH2OH while that of water is H-OH. The intermolecular forces in both water and glycerol are the strong H-bonds. However, since there are 3 OH groups/ glycerol molecule vs the one -OH group in water enables glycerol to form more H-bonds when compared to water.

The stronger attractive forces in glycerol causes an increase in its boiling point.

klio [65]3 years ago

6 0

Answer: Glycerol has more attractive forces as compared to water.

Explanation:

Boiling point is the temperature at which vapor pressure of the liquid becomes equal to atmospheric pressure.

Boiling point depends on the strength of inter molecular forces.

The molecules of glycerol $(HOCH_2CH(OH)CH_2OH)$ are more strongly bonded through hydrogen bonds as there are three OH groups.

But in water $(H_2O)$ , only on e OH group is present and thus extent of hydrogen bonding is less.

Thus we can conclude that glycerol has more attractive forces as compared to water.

You might be interested in

If 7.84 × 107 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3

yanalaym [24]

The correct answer would be 8.71 × 10–10

6 0

3 years ago

A molecular compound is?

Nezavi [6.7K]

Composed of molecules formed by atoms of two or more different elements.

3 0

4 years ago

Read 2 more answers

Methane, a component in natural gas, can be used as a fuel in combustion reactions. What is the value for ΔGnon (in kJ) for the

Oksanka [162]

Answer: The $\Delta G$ for the reaction is -806.86 kJ

Explanation:

We are given:

$\Delta H^o_{rxn}=-803kJ=-803000J$ (Conversion factor: 1 kJ = 1000)

$\Delta S^o_{rxn}=-4.05J/K$

Temperature of the reaction = 293 K

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

$\Delta G^o_{rxn}=\Delat H^o_{rxn}-T\Delta S^o_{rxn}$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=-803000J-[(293K)\times (-4.05J/K)]=-801813.35J$

For the given chemical equation:

$CH_4(g)+2O_2(g)\rightleftharpoons CO_2(g)+2H_2O(g)$

The expression for $K_c$ is given as:

$K_{c}=\frac{[H_2O]^2[CO_2]}{[CH_4][O_2]^2}$

We are given:

$[H_2O]=6.41M$

$[CO_2]=3.83M$

$[CH_4]=14.51M$

$[O_2]=9.27M$

Putting values in above equation, we get:

$K_c=\frac{(6.41)^2\times 3.83}{14.51\times (9.27)^2}$

$K_c=0.126$

To calculate the Gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_c$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = -801813.35 J

R = Gas constant = $8.314J/K mol$

T = Temperature = 293 K

$K_c$ = equilibrium constant in terms of concentration = 0.126

Putting values in above equation, we get:

$\Delta G=-801813.35J+(8.314J/K.mol\times 293K\times \ln(0.126))$

$\Delta G=-806859.46J=-806.86kJ$

Hence, the $\Delta G$ for the reaction is -806.86 kJ

8 0

3 years ago

1. Who is the father of atomic theory? 2. Who discovered the electron? 3. Who expressed particles by wave equations? 4. Who rese

krek1111 [17]

1. Who is the father of atomic theory?
Dalton

2. Who discovered the electron?
Thomson

3. Who expressed particles by wave equations?
Schrödinger

4. Who researched on radioactivity?
Curie

5. Who discovered the "open spaces" model?
Rutherford

6. Who applied quantum theory to atoms?
Bohr

6 0

4 years ago

Read 2 more answers

What is the ph of a 0.001 62 m naoh solution?

marin [14]

The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log [ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20

4 0

3 years ago