1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LenKa [72]
3 years ago
11

D.new

Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0
I think the answer is B
You might be interested in
What is the radius of a circle i<br>s ​
Nonamiya [84]

Answer:

The Radius is the distance from the center outwards. The Diameter goes straight across the circle, through the center. The Circumference is the distance once around the circle.

6 0
3 years ago
Read 2 more answers
A solution is prepared by dissolving 27.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
bagirrra123 [75]
The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is 
     % by mass = (mass of the solute / mass of the solution)*100 
                        = mass of solute / (mass of the solute + mass of the solvent)*100
                        = (27.7 g CaCl2 / 27.7g + 375g) * 100 
                        = 6.88
5 0
4 years ago
Read 2 more answers
How much of a sample remains after three half-lives have occurred? 1/16 of the original sample 1/9 of the original sample 1/8 of
Drupady [299]
For this question, assume that you have 1 compound. This compound is divided in half once, so you are left with 0.5. That 0.5 that remains is divided in half again, this is the second half-life, and you are left with 0.25. The final half life involves dividing 0.25 in half, which means you are left with 0.125. For the answer to make sense, you need to know your conversions between decimals and fractions. To make it simple, if you have 0.125 and you times it by 8, you are left with your initial value of 1. Therefore, after three half-lives, you are left with 1/8th of the compound.
5 0
3 years ago
Read 2 more answers
2CO + O2 --&gt; 2CO2
GREYUIT [131]

Answer:

10 L of CO₂.

Explanation:

The balanced equation for the reaction is given below:

2CO + O₂ —> 2CO₂

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Finally, we shall determine the volume of CO₂ produced by the reaction of 10 L CO. This can be obtained as follow:

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Therefore, 10 L of CO will also react to produce 10 L of CO₂.

Thus, 10 L of CO₂ were obtained from the reaction.

3 0
3 years ago
Why weren’t scientists initially concerned that the ocean absorbs excess carbon dioxide?
nasty-shy [4]
They only discovered
5 0
3 years ago
Other questions:
  • Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.​
    13·2 answers
  • Are the particles in a solid motionless ?
    9·1 answer
  • Which of the following compounds is soluble in water?
    12·2 answers
  • Corbin burned with oxygen to produce carbon dioxide gas what is the correct chemical reaction
    10·1 answer
  • The volume measuring system for a gasoline pump at the service station is calibrated at 20.0°C. If the temperature of the gasoli
    14·1 answer
  • A 25.0 ml sample of 0.723 m hclo4 is titrated with a 0.273 m koh solution. the h3o concentration after the addition of 50.0 ml o
    9·1 answer
  • How many lone pairs of electrons are represented in the Lewis structure of a phosphate ion (PO43-)? 10 12 21 24
    15·1 answer
  • If I perform a dilution, which is true? *
    12·1 answer
  • __HgO __Hg + __O2 what is the reaction
    9·1 answer
  • Whichstatement describes a question that can be answered by a scientific investigation
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!