1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aliina [53]
3 years ago
15

If the pressure and moles of a gas are held constant, the volume of a gas increases by the same factor as the temperature.

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
4 0
The answer to this problem is True
You might be interested in
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0
1 year ago
Aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge. Please select the best answer fr
Luden [163]
<h2>Answer:</h2>

True

<h2>Explanation:</h2>

we can describe aptitude as an innate ability of a person to do something. There are different aptitude test in which we test the skills and ability to do different work or his attitude toward success or failure.

So, we can say that aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge.

4 0
3 years ago
Read 2 more answers
I need help with these two if you zoom in it’s clearer
makvit [3.9K]

Answer:

It looks alittle dark can you fix it?

3 0
3 years ago
How many atoms doesCo(NO3)2 have
svet-max [94.6K]
The answer is 9. Calcium nitrate is made up
of 3 different elements that equal 9 atoms.
7 0
3 years ago
Read 2 more answers
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
Other questions:
  • Draw and label the parts of a helium atom. Include the mass and charge of each subatomic particle.
    10·1 answer
  • Water molecules on aluminum foil is an example of ____. a density b. freezing c. cohesion d. adhesion
    14·1 answer
  • what is the daughter nucleus (nuclide) produces when 64^Cu undergoes beta decay by emitting an electron? replace ? ? ?
    5·1 answer
  • When an object such as a rock is dropped into water it disturbs the surface of the water waves form at the surface of the water
    11·1 answer
  • A 2.832 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 6.439 grams of CO2 and 2
    6·1 answer
  • A certain substance X has a normal boiling point of 117.8°C and a molal boiling point elevation constant =Kb·0.63°C·kgmol−1. A s
    12·1 answer
  • What is the formula for CO3 2- and Al3+ ?
    5·2 answers
  • How much of a 15.0M stock solution do you need to prepare 250ml of a 2.35ml hf solution?
    7·1 answer
  • Consider these two entries from a fictional table of standard reduction potentials.
    13·1 answer
  • NH4NO3, (aq) + Ba(OH)2(aq) →
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!