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Sphinxa [80]
2 years ago
10

A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven i

nfants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. When evaluated using the 5% level of significance, which of the following would be the best decision/interpretation of the null hypothesis?
A. Fail to reject the null hypothesis.

B. Reject the null hypothesis and conclude the mean is higher than 6.6 lbs.

C. Reject the null hypothesis and conclude the mean is lower than 6.6 lbs.

D. Cannot calculate because the population standard deviation is unknown.
Mathematics
1 answer:
kolbaska11 [484]2 years ago
3 0

Answer:

A. Fail to reject the null hypothesis.

Step-by-step explanation:

We are given with the Population mean weight of newborn infants at a community hospital, \mu = 6.6 pounds

Now the sample data of seven infants with their weights at birth is given as:

6.0, 6.6, 6.8, 7.3, 8.4, 8.8, 9.0

Sample Mean, Xbar = \frac{\sum X_i}{n} where Xi are the each data value

                                                         and n = sample size

                                 = \frac{6.0+ 6.6+ 6.8+ 7.3+ 8.4+ 8.8+ 9.0 }{7} = 7.56

Sample Standard Deviation, s = \sqrt{\frac{\sum (X_i-Xbar)^{2}}{n-1}} = 1.18

  Let Null hypothesis, H_0 : \mu = 6.6 pounds

  Alternate hypothesis, H_1 : \mu > 6.6 pounds

Since we don't know about population standard deviation so the test statistics we use here will be :

                   \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } follows t distribution with (n-1) degree of freedom [t_n_-_1]

   Test Statistics = \frac{7.56-6.6}{\frac{1.18}{\sqrt{7} } } follows t_6

                           = 2.1525

<em>At 5% level of significance  </em>t_6<em> has a value of 1.943 but our test statistics is higher than this so we have sufficient evidence to accept null hypothesis and conclude that mean is 6.6 pounds.</em>

Therefore, option A is correct that we Fail to reject the null hypothesis.

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m_a_m_a [10]
Add 8 to 46. Then divide 54/8 to get 6.75 and t=6.75
5 0
2 years ago
Help me answer this q1
Ostrovityanka [42]

Answer: B is the answer yup B

6 0
3 years ago
Eddie walks 450.25 feet in 2.5 minutes. Which value is closest to the number of yards Eddie walks in 1 minute?
Anna71 [15]

Eddie walks 60.03 yards in 1 minute using proportion.

What is proportion?

The term proportionality refers to any relationship that has the same ratio every time. The proportional relationship between the two supplied ratios is defined by an equation. In other terms, the proportion declares that the two fractions or ratios are equal. For instance, the average number of apples per tree determines the proportionality between the quantity of apples in a crop and the number of trees in the orchard.

Here let us take time and distance as proportional values,

=> \frac{distance}{Time}

=> 450.25/2.5 = x/1

=> x = 180.1 feet.

To convert feet to yards divide the length by 3. then

=> 180.1/3=60.03 yards,

Therefore Eddie Walks 60.03 yards in 1 minute.

To learn more about proportion refer the below link

brainly.com/question/19994681

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7 0
10 months ago
An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s
maks197457 [2]

Answer:

W_s \approx5.3

Step-by-step explanation:

From the question we are told that

Height H=3.5ft

Weight W= 6ft

Depth  D=0.95ft

Generally the equation for ellipses is given as

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

Where

b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\

\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1

Generally to find y in the equation \frac{x^2}{a^2} +\frac{y^2}{b^2} =1

y=-b+d

y=-1.75+0.95

y=-0.8

Therefore

\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1

\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}

\frac{x^2}{3^2} =1-0.2089795918

X^2 =3^2(1-0.2089795918)

X^2 =7.119183674

X =\sqrt{7.119183674}

X =2.66817984

Therefore the width of the given stream is

W_s=2.66817984*2

W_s=5.33635968

W_s \approx5.3

3 0
3 years ago
(HELP ME )Jolie played dodgeball in PE. In one game, Jolie threw a total of 75 balls at her
ollegr [7]

Answer:

40%

Step-by-step explanation:

A percent is;

\frac{part}{whole}  = \frac{x}{100}

It is given that Jolie the 75 dodgeballs in total, hence the whole is 75. It is also given that 30 of the dodgeballs hit the target, so the part is 30. Now all one has to do is solve for "x".

\frac{30}{75} = \frac{x}{100}

Simplify \frac{30}{75} by dividing the numerator and denominator by 15.

\frac{2}{5}

Now the equation is;

\frac{2}{5}=\frac{x}{100}

Typically, one would solve a proportion by doing cross products, but in this case, it is easier to think about it intuitively. Since 5 is a factor of 100 (5 * 20 = 100), then all one has to do is multiply \frac{2}{5} by 20 to get the answer (on the numerator).

x = 40

7 0
3 years ago
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