All categories

3 years ago

PLEASE HELP ASAP!!!!!

Mathematics

1 answer:

pychu [463]3 years ago

6 0

Answer:

Parallel

Step-by-step explanation:

They're Parallel because whenever you graph them you see they never touch.

You might be interested in

7: Jikayla earns $19 per hour babysitting. Last week, she worked 7 hours on Monday, 6 hours on Tuesday, and 7 hours on Wednesday

____ [38]

Answer:

$475

Step-by-step explanation:

7+6+7+5 = 25

25*19 = 475

6 0

4 years ago

Is one a polygon, two, three?

loris [4]

Answer:

1 and 2 is and 3 is not

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the number sentence for "1 less than N is the sum of Z and<br> 2"?

s344n2d4d5 [400]

$\rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>What is the number sentence for "1 less than n is the sum of z and 2?"</em>

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

❖ First, Notice it says "1 less than n". This expression indicates that

we subtract 1 from n, which looks as follows:-

$\Large\textit{n-1}$

❖ Now, It also says "the sum of z and 2". This indicates that we add z and

2:-

$\Large\textit{z+2}$

❖ Now, Combine these two little expressions into one equation:-

$\implies\sf{n-1=z+2}$

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

$\rule{300}{1}$

6 0

2 years ago

Five more than three times a number is 131. Find the number.

Crazy boy [7]

The answer would be 42
42*3 = 126
126+5 = 131
3(n)+5=131
3(n)+5 -5= 131-5
3(n)=126
3(n)/3= 126/3
n= 42

6 0

3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

3 years ago