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3 years ago

Can anyone find me a chapter 10 extra credit for algebra 1

Mathematics

1 answer:

inysia [295]3 years ago

7 0

Answer:

i think i found it, but you might have to print it out, but i will send the link: https://www.murrieta.k12.ca.us/cms/lib5/CA01000508/Centricity/Domain/1791/_Files/Algebra%201/c10rev.pdf

:) have a nice day love ❤

Step-by-step explanation:

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Answer:

$\textrm{Resultant velocity}\ =\ \sqrt{29}\ miles/hour$

along the direction 68.19° from north.

Step-by-step explanation:

Given,

speed of the boat, u= 2 miles/hour along north

speed of the river, v= 5 miles/ hour along east

Since, north and east are perpendicular to each other, so we can write the resultant velocity in vector form as,

$\vec{r}\ =\ 2\hat{i}+5\hat{j}$

Hence, the magnitude of resultant velocity can be written as

$r\ =\ \sqrt{2^2+5^2}$

$=\ \sqrt{4+25}$

$=\ \sqrt{29}$

Hence, the magnitude of resultant vector is \sqrt{29} moles/hour.

And the direction of the boat can be given by,

$tan\theta\ =\ \dfrac{5}{2}$

$=>\ tan\theta\ =\ 2.5$

$=>\ \theta\ =\ tan^{-1}2.5$

= 68.19°

Hence, the resultant velocity of boat is $\sqrt{29}$ miles/hour along the direction making an angle 68.19° with the north.

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