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nexus9112 [7]
3 years ago
9

kenneth’s shoe repair shop borrowed 6600$ from a bank at 8% simple interest per annum.how much did he owe the bank at the end of

11 months?
Mathematics
2 answers:
Airida [17]3 years ago
8 0

Answer:

$7084

Step-by-step explanation:

The formula for Simple interest is P×R×T÷100

P= Principal amount (amount borrowed) $6600, R= Rate 8%, T= Time in years 11/12years

Since the question says for 11months, one has to convert 11months to years which is 11/12years or 0.9166years

Next, insert the figures into the formula to get the interest

6600×8×11/12 ÷ 100

After solving, we get $484 as the Simple interest

To get the amount owed at the end of 11months, we then add the interest $484 and the borrowed amount $6600= $7084

marishachu [46]3 years ago
6 0
Kenneth owed the bank 5,808$ per annum..
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