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timurjin [86]
3 years ago
12

Describe the appearance of the material. Include its color and state (solid or liquid). Pour ¼ cup of water into a small, clear

container. Measure ¼ teaspoon of the material, and carefully pour it into the container. Look at the side of the container as you pour in the material. Decide whether the material is less dense or more dense than water by observing whether the material floats or sinks. Swirl the container to see whether the material mixes with the water.
Chemistry
2 answers:
Alex777 [14]3 years ago
5 0

<u>Answer:</u>

<em>Here the given material is taken and mixed with water.</em>

<u>Explanation:</u>

The amount of material and water taken are same. Hence if it is not soluble in water it should make a dense and flowy paste like material and if it is soluble in water it should this and thicker density of water should remain.

If the amount of water that we are taking is more than the material will float in water if it is not soluble and lighter than water or would sink if it is heavier than water.

DIA [1.3K]3 years ago
4 0

Answer:

This is a test of the density and solubility of the given material in water.

Explanation:

The density of a material is a measure of the weight of the material and is defined as the 'mass per unit volume.'

If the material is denser than water, then the material will sink and form a distinct layer at the bottom of the container.

However, if the material is less dense than water, then the material will float on the surface of water in the container.

On swirling the container, if the material dissolves in water then the material is soluble and mixes with water.

On the other hand, if it doesn't dissolve and forms a distinct layer either on the surface or at the bottom of the container, then the material is insoluble in water.

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Chemistry help!
Delvig [45]

Answer: C, B, A

Explanation:

C is the initial solution, because naoh has not been added yet

B is the midpoint of the titration.  naoh has been added to the solution, but it has not fully reacted yet. You can tell that this one is the midpoint because there is still HF- in the diagram, which is not one of the products formed in the reaction.

A is the endpoint because the diagram shows that all products are fully formed. There is an increased amount of Na+ and H2O in the diagram and no HF- left.  

PS. I tested this answer on the concentration of acetic acid post-lab (from mcgraw hill) earlier today and it said this was the right answer :) hope this helps

3 0
3 years ago
A 25.0 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution. The titration curve above was ob
Mnenie [13.5K]

Answer:

Weak acid

Explanation:

A titration curve is a graphical description of the change in pH of the solution in the conical flask as the reagent is added from the burette. A titration curve can be plotted for the different kinds of acid and base titrations. The volume of the titrant is always plotted as the independent variable and the pH of the solution as the dependent variable. The equivalence point is read off from the titration curve. A titration curve is very important because it shows the pH at various points during the titration.

A weak acid/strong base titration leads to an equivalence point above 7. From the question, we were told that the pH at equivalence point lies around 8. Hence the unknown substance must be a weak acid.

3 0
4 years ago
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