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timurjin [86]
2 years ago
12

Describe the appearance of the material. Include its color and state (solid or liquid). Pour ¼ cup of water into a small, clear

container. Measure ¼ teaspoon of the material, and carefully pour it into the container. Look at the side of the container as you pour in the material. Decide whether the material is less dense or more dense than water by observing whether the material floats or sinks. Swirl the container to see whether the material mixes with the water.
Chemistry
2 answers:
Alex777 [14]2 years ago
5 0

<u>Answer:</u>

<em>Here the given material is taken and mixed with water.</em>

<u>Explanation:</u>

The amount of material and water taken are same. Hence if it is not soluble in water it should make a dense and flowy paste like material and if it is soluble in water it should this and thicker density of water should remain.

If the amount of water that we are taking is more than the material will float in water if it is not soluble and lighter than water or would sink if it is heavier than water.

DIA [1.3K]2 years ago
4 0

Answer:

This is a test of the density and solubility of the given material in water.

Explanation:

The density of a material is a measure of the weight of the material and is defined as the 'mass per unit volume.'

If the material is denser than water, then the material will sink and form a distinct layer at the bottom of the container.

However, if the material is less dense than water, then the material will float on the surface of water in the container.

On swirling the container, if the material dissolves in water then the material is soluble and mixes with water.

On the other hand, if it doesn't dissolve and forms a distinct layer either on the surface or at the bottom of the container, then the material is insoluble in water.

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For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
2 years ago
Identify the decomposition reaction. 2nh3 + h2so4 ⟶ (nh4)2so4 2nabr + ca(oh)2 ⟶ cabr2 + 2naoh 2 no2 ⟶ 2 o2 + n2 3pb + 2h3po4 ⟶ 3
TEA [102]

A decomposition reaction should look like

A ------> B +C+...

It has to have only one reactant and several products.

2 NO2 ⟶ 2 O2 + N2

7 0
3 years ago
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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati
babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}

Here, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 1
  • H = 2
  • Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply H_{2}O by 2 on product side. Therefore, the equation can be rewritten as follows.

MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}

Hence, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

6 0
3 years ago
Which element melts at room temperature?
just olya [345]
Francium is an element that melts at room temperature. Francium is a highly reactive element, and only contains one valence electron, which is very ironic in my opinion. 
4 0
3 years ago
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The mass number of an element is equal to ____.
melisa1 [442]
Mass number is the total number of protons and neutrons in the nucleus
4 0
3 years ago
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