AB over DE = BC over EF
AC over DF = BC over EF
Answer:
-4 ± 2*sqrt(3)
Step-by-step explanation:
Well I'm not quite sure as to what the x= equations are, but for the solution to this quadratic I just used the quadratic formula. This gave me -8 ± sqrt(48)/2, which can be simplified to -4 ± 2 * sqrt(3). Hope this helps :)
Answer:
f1: 0.440, f2: 0.931, f3: 1.519
Step-by-step explanation:
To solve the system of equations we need to use the inverse of matrix A, as follows:
A x F = C
A^-1 x A x F = A^-1 x C
I x F = A^-1 x C
where I is the identity matrix.
The inverse of A is:
1.450 -0.392 -0.090
A^-1 = -0.074 -0.022 0.1536
-0.406 0.7122 -0.060
(computed with Excel)
The multiplication between the inverse of A and C gives:
0.440
A^-1 x C = 0.931
1.519
(computed with Excel)
Answer:
f(-1) = -1 . . . . matches the last selection
Step-by-step explanation:
When evaluating piecewise functions, the first step is to determine the applicable piece. The argument -1 is in the range of the middle definition, (-2, 1). So, the function value is ...
... (-1)³ = -1