Ask question

Ask question

All categories

4 years ago

13

When you flick a coin so that it slides across a table, what four forces are acting on the coin?

2 answers:

Kamila [148]4 years ago

8 0

<u>Any time the coin is on the table:</u>
-- gravity acting downwards
-- normal force of the table, acting upwards

<u>Any time the coin is moving:</u>
-- friction force, on the coin's underside
-- air resistance
Both of these act opposite to the direction of the coin's motion.

<u>During the flick, while your finger is still touching the coin:</u>
-- the flicking force, a push exerted by your finger
The force ends as soon as the coin leaves contact with your finger.

Nadusha1986 [10]4 years ago

3 0

Pushing force
friction
gravity
normal force

You might be interested in

A 800hz tuning fork is vibrating, producing a sound wave in the air.

blsea [12.9K]

Answer:

The frequency of the sound wave is 800Hz

The speed of sound in a is about 340m/s.

Velocity = frequency x wavelength

making wavelength the subject formula

wavelength = Velocity/frequency.

wavelength = 340/800

wavelength = 0.425m.

3 0

2 years ago

2. Three charged particles are placed at the corners of an equilateral triangle of side 1.20 m. The charges are +7.0μC, -8.0 μC

Scorpion4ik [409]

Answer:

0.53 N, 25.6°

Explanation:

side of triangle, a = 1.2 m

q = 7 μC

q1 = - 8 μC

q2 = - 6 μC

Let F1 be the force between q and q1

By using the coulomb's law

$F_{1}=\frac{Kq_{1}q}{a^{2}}$

$F_{1}=\frac{9\times 10^{9}\times 7\times 10^{-6}\times 8\times 10^{-6}}{1.2^{2}}$

F1 = 0.35 N

Let F2 be the force between q and q2

By using the coulomb's law

$F_{2}=\frac{Kq_{2}q}{a^{2}}$

$F_{2}=\frac{9\times 10^{9}\times 7\times 10^{-6}\times 6\times 10^{-6}}{1.2^{2}}$

F2 = 0.26 N

Write the forces in the vector form

$\overrightarrow{F_{1}}=0.35\widehat{i}$

$\overrightarrow{F_{2}}=0.26\left ( Cos60 \widehat{i}+Sin60\widehat{j}\right )$

$\overrightarrow{F_{2}}=0.13 \widehat{i}+0.23\widehat{j}$

Net force

$\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}$

$\overrightarrow{F}=0.48 \widehat{i}+0.23\widehat{j}$

Magnitude of the force

$F=\sqrt{0.48^{2}+0.23^{2}}$

F = 0.53 N

Direction of force with x axis

$tan\theta =\frac{0.23}{0.48}$

θ = 25.6°

7 0

3 years ago

Which of Newton's motion laws BEST explains HOW a rock accelerates when it is dropped off a bridge?

ki77a [65]

Answer:

a

Explanation:

6 0

4 years ago

Read 2 more answers

Katlyn makes a gelatin dessert. She pours hot water into the flavored gelatin powder and stirs. What are the solute and solvent

Novosadov [1.4K]

Katlyn pours hot water into the flavored gelatin powder and stirs.

Gelatin powder is the solute. Water is the solvent. <em>(D)</em>

6 0

3 years ago

An object cannot have a charge of

Andreas93 [3]

Answer:

hi

Explanation:

8 0

3 years ago