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3 years ago

When you flick a coin so that it slides across a table, what four forces are acting on the coin?

2 answers:

8 0

Any time the coin is on the table:
-- gravity acting downwards
-- normal force of the table, acting upwards

Any time the coin is moving:
-- friction force, on the coin's underside
-- air resistance
Both of these act opposite to the direction of the coin's motion.

During the flick, while your finger is still touching the coin:
-- the flicking force, a push exerted by your finger
The force ends as soon as the coin leaves contact with your finger.

Nadusha1986 [10]3 years ago

3 0

Pushing force
friction
gravity
normal force

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3 years ago

An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i

crimeas [40]

Answer:

It is real, inverted, and smaller than the object.

Explanation:

Let's start by using the lens equation to find the location of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}$

where we have:

q = ? is the distance of the image from the lens

f = 15 cm is the focal length (positive for a converging lens)

p = 50 cm is the distance of the object from the lens

Solving the equation for q, we find

$\frac{1}{q}=\frac{1}{15 cm}-\frac{1}{50 cm}=0.047 cm^{-1}$

$q=\frac{1}{0.047 cm^{-1}}=+21.3 cm$

The sign of q is positive, so the image is real.

Now let's also write the magnification equation:

$h_i = - h_o \frac{q}{p}$

where

$h_i, h_o$ are the size of the image and of the object

By substituting p = 50 cm and q = 21.3 cm, we find

$h_i = - h_o \frac{21.3 cm}{50 cm}=-0.43 h_o$

So we notice that:

$|h_i| < |h_o|$ : this means that the image is smaller than the object

$h_i < 0$ : this means that the image is inverted

so, the correct option is:

It is real, inverted, and smaller than the object.

7 0

3 years ago

What equation gives the position at a specific time for an object with constant acceleration?

malfutka [58]

Given constant acceleration, we can get the final position of an object in terms of both its initial velocity and its acceleration using one of the equations of motion.

The equation that we will use is:
Xf = Xi + Vi*t + (1/2)*a*t^2
where:
Xf is the final position of the object
Xi is the initial position of the object
Vi is the initial velocity of the object
t is the time
a is the constant given acceleration

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3 years ago

An 80.0 N force accelerates a 6.0 kg object from 4.0 m/s to 8.0 m/s. What is the

kolezko [41]

Answer:

24kgm/s

Explanation:

Given parameters:

Force = 80N

Mass of object = 6kg

Initial velocity = 4m/s

Final velocity = 8m/s

Solution:

Impulse = ?

Solution:

The impulse on a body is its change in momentum.

Impulse = m (v - u )

m is the mass

v is the final velocity

u is the initial velocity

Now insert the parameters and solve;

Impulse = 6 (8 - 4) = 24kgm/s

8 0

2 years ago