Answer:
the bearing of the angle AC will be equal to 154°51' 48"
Explanation:
given,
bearing of line AB = 234° 51' 48"
C is anti clockwise angle from 80° from AB
bearing of line AC = ?
To calculate the bearing of line AB 80° anticlockwise movement
bearing of the AC = 234° 51' 48" - 80°
= 154°51' 48"
The bearing can be represented as 154.5148
hence, the bearing of the angle AC will be equal to 154°51' 48"
Lamina occupies x² + y² = 14y. Outside circle is x² + y² = 49
To find the mass of lamina, integrate given density function over the region
m = ∫∫D P(x, y) dA
Subtitute x = r cosФ and y = r sinФ in x² + y² = 14y
and x² + y² = 49
x² + y² = 14y
(r cosФ)² + ( rsinФ)² = 14(rsinФ)
r² = 14r sin Ф
x² +y² = 49
r² = 49
r = 7
Cntre mass (-x. -y)
-x= i/m ∫∫D xp(x,y) dA = 1/m∫∫ (r cosФ) p( r, Ф)r
dr dФ
-y = 1/m∫∫D yp(x, y) dA = 1/m ∫∫D (r sinФ) p(r, Ф) r drФ
where m = ∫∫D p(x, y) dA
C. 18 N:s West ksmxmak kxkammxj kan
The magnification formula is:
M = H (i)/H (o) = -D (i)/D (o)
In other words, the ratio of the image distance and object distance to the ratio of the image height and the object height.