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777dan777 [17]
3 years ago
14

Normal force is exerted _____to the surface of an object.

Physics
2 answers:
denis23 [38]3 years ago
7 0
<h2>Answer:</h2>

<u>The correct option is </u><u>A. perpendicular</u>

<h2>Explanation:</h2>

In Physics, the normal force is the component of a contact force that is perpendicular to the surface that an object contacts. It is the support force exerted upon an object that is in contact with another stable object. Normal Force will be always acting opposite to the force falling on the surface. For example, if a book is resting upon a surface, then the surface is exerting an upward force upon the book in order to support the weight of the book.

Elanso [62]3 years ago
3 0

The normal force is always (underline, bold) is always perpendicular to the surface an object is sitting on. If the object is on an inclined plane, then the normal will not be vertical but it will be perpendicular to the angle of the incline.

The diagram below (left) shows a normal force (GH) that is not vertical, but it is perpendicular to the surface. The object on the right is the more usual normal a mass on a table top.

The vertical line on the right is the normal and it points up.

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The voltage across a conductor is increasing at a rate of 2 volts/min and the resistance is decreasing at a rate of 1 ohm/min. U
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3.5 amperes

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I = E/R

I = ?

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3 0
3 years ago
According to Oxford Dictionaries, a spit take is an act of suddenly spitting out liquid one is drinking in response to something
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Answer:

The pressure is p_1 = 4051.4 \ Pa

Explanation:

From the question we are told that

     The gauge pressure at the mouth is  p_1

     The radius of the column is  r_2 =  4 \ mm  =  0.004 \ m

    The speed of the liquid outside the body is  v_2 =  3.1 \ m/s

      The area of the column is  A_2

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       v_1 A_1 =  v_2 A_2

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=>        v_ 1 = 0.31 \ m/s

So

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substituting values

        r_1 = 10 * 0.004

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Now the height of inside the mouth is  h_1 =  d =  2r_1 =  2* 0.04 =  0.08\ m

Now the height of the column is  h_2 =  d =  2r_2 =  2* 0.004 =  0.008\ m

Generally according to Bernoulli's  equation

        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

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        p_2 is the gauge pressure of the atmosphere which is  zero

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       p_1 =  [(0.5 * 1000 * (3.1)^2) +(0.008 * 1000 * 9.8) + 0]-

                                                  [(0.5 * 1000 * 0.31^2) + (0.08*1000 * 9.8)]                          

       p_1 = 4051.4 \ Pa

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