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Dmitry [639]
3 years ago
14

What feature best distinguishes one form of electromagnetic energy from another?

Physics
1 answer:
anastassius [24]3 years ago
3 0

The family of electromagnetic waves ranges from the Long Radio waves to the gama rays.

All of that contain electromagnetic energy and move at the speed of light.

But what distinguish one from another is their wavelengh.

Or, if you like, its counterpart: their frequency. (as can be seen in the equation c = λ . f   where c is the speed of light, λ is the wavelengh and f is the frequency).

The shorter the wavelengh (the greater the frequency) more powerful (more energy it contains) is the electromagnetic wave.

From all the different kinds of electromagnetic waves of the spectrum, the less powerful (less energetic) are the Long Radio waves (λ in metres) and the more powerful ones are the gama rays (λ in 10^{-12} m).

:-)

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Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r
madam [21]

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

E= K\frac{q}{r^{2} } --> r=\sqrt{\frac{kq}{E} } Despejas "r"

Resuelves

<h3>r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9}  C)}{6000N/C} }  (la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>
4 0
3 years ago
You are on the south bank of the river in your canoe you need to reach the north bank you know that you can row your canoe at 2
Anna71 [15]

Answer:

(θ) = 60°

Explanation:

Given:

Speed of canoe Vc = 2 m/s

Speed of River Vr = 1 m/s

Computation:

Vc (Cosθ) = Vr

2 (Cosθ) = 1

(Cosθ) =  1 / 2

(Cosθ) = (Cos60)

(θ) = 60°

3 0
2 years ago
What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
Goshia [24]

Answer:

a) R_s = 0.092

b) R_p = 0.085

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

3 0
3 years ago
Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha
Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}

It means she can send 52 oranges and it is maximum quantity.

4 0
3 years ago
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