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LenaWriter [7]
3 years ago
15

Is the work correct?

Chemistry
1 answer:
Brums [2.3K]3 years ago
5 0
Looks good to me but re review the 8 and make sure it's correct
You might be interested in
What are some examples of how electrolysis is used in scientific research ?
charle [14.2K]

Answer:

Explanation: Perhaps the most familiar example of electrolysis is the decomposition (breakdown) of water into hydrogen and oxygen by means of an electric current. The same process can be used to decompose compounds other than water. Sodium, chlorine, magnesium, and aluminum are four elements produced commercially by electrolysis.

6 0
2 years ago
Can someone please help me
Vanyuwa [196]

Answer:

1.7

Explanation:

Density = M/V

When you divide 4.52 by 2.6, you get 1.738461538, which can be simplified to 1.7.

7 0
2 years ago
How many molecules are in 9.44 moles of AICI3?
Keith_Richards [23]

Answer:

5.68x1024 molec AICI:

8 0
2 years ago
50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the
trapecia [35]

Answer:

-21 kJ·mol⁻¹  

Explanation:

Data:

                    H₃O⁺ +  OH⁻ ⟶ 2H₂O

       V/mL:    50         50  

c/mol·dm⁻³:   1.0         1.0

     

ΔT = 4.5 °C  

       C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

     nΔH   +         mCΔT       + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 +   50×4.5  = 0

0.050ΔH +          1883        +      225    = 0

                                  0.050ΔH + 2108 = 0

                                              0.050ΔH = -2108

                                                        ΔH = -2108/0.0500

                                                              = -42 000 J/mol

                                                              = -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

5 0
3 years ago
The ionic equations represent the reactions between four metals, P, Q, R and S, and solutions of the salts of the same metals
EleoNora [17]

Answer:

P + Q2+ -> no reaction

R + P2+ -> R2+ + P

Q + S2+ -> Q2+ + S

S + P2+ -> S2+ + P

S + R2+ -> S2+ + R

S + Q2+ -> no reaction

What is the correct order of reactivity of the metals?

Most -----------------------> least

A. P R S Q

B. Q R S P

C. Q S R P

D. S Q P Rhhgu

5 0
3 years ago
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