All categories

2 years ago

3. How would you expect the density of the gummy bear to change if you soaked it in isopropanol (rubbing alcohol, density

Chemistry

1 answer:

77julia77 [94]2 years ago

7 0

Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

<h3>Effects on density by soaking isopropanol</h3>

We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.

If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

Learn more about density here: brainly.com/question/1354972

You might be interested in

Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying

PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? ( $K_a$ for HF is $6.8\times 10^{-4}$ .)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = $K_a=6.8\times 10^{-4}$

$HF\rightleftharpoons H^++F^-$

Initially

c 0 0

At equilibrium :

(c-x) x x

The expression of disassociation constant is given as:

$K_a=\frac{[H^+][F^-]}{[HF]}$

$K_a=\frac{x\times x}{(c-x)}$

$6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}$

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

$[H^+]=x=0.01346 M$

The pH of the solution is ;

$pH=-\log[H^+]=-\log[0.01346 M]=1.87$

The pH of an 0.280 M HF solution is 1.87.

6 0

3 years ago

(04.03 LC)

pishuonlain [190]

Carrying capacity, D
Emigration, C
Limiting factor, A
Population dynamics, B

4 0

3 years ago

What is the relationship between the Kuiper Belt and the status of Pluto today?

Xelga [282]

Pluto is a dwarf planet, but one of the largest known members, in the Kuiper belt.

The Kuiper Belt extends between 30 AU and 55 AU from the Sun

(1 AU = 1.5 × 10^8 km = distance from Earth to Sun).

Pluto's orbit is highly elliptical. It ranges from 30 AU to 50 AU. When Pluto is closest to the Sun, it is inside the orbit of Neptune (30 AU).

Astronomers class Pluto as a <em>resonant Kuiper belt object</em> (KBO). Because it gets so close to Neptune, its orbit is in <em>resonance</em> with that of Neptune. Pluto makes two orbits for every three of Neptune.

4 0

3 years ago

What happens to the volume of a gas in a closed container if the temperature increases, but the pressure remains the same? Why?

labwork [276]

Answer:

Volume will goes to increase.

Explanation:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

So when the temperature goes to increase the volume of gas also increase. Higher temperature increase the kinetic energy and molecules move randomly every where in given space so volume increase.

Now we will put the suppose values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 4.5 L × 348 K / 298 k

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

Hence prove that volume increase by increasing the temperature.

3 0

3 years ago

How many hydrogen atoms are there in the molecule H2SO?

sergiy2304 [10]

Answer:

D:2

Explanation:

H is hydrogen, and the subscript represents the amount of atoms it has so H2SO is two hydrogens

3 0

3 years ago

Read 2 more answers