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2 years ago

3. How would you expect the density of the gummy bear to change if you soaked it in isopropanol (rubbing alcohol, density

Chemistry

1 answer:

77julia77 [94]2 years ago

7 0

Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

<h3>Effects on density by soaking isopropanol</h3>

We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.

If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.

Learn more about density here: brainly.com/question/1354972

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If an electrostatically charged object is placed near other objects, which of the following will occur? Select all that apply. I

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Answer:

As the electrostatically charged object is to be placed in the field of charged particles it will be attracted to those who would be of oppositely charged and repelled by the same charged particles. phenomenon of like charges repel and opposite charges attract each other will be carried out and no deflection will be shown by the charge towards the neutral charge.

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3 years ago

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Which one of the following statements BEST describes a chemical reaction?

Natalija [7]

Answer: The correct statement is (A new substance is formed and the process can usually NOT be undone.)

Explanation:

A chemical reaction is simply defined as the reaction between two or more elements in which a new substance is formed and the process can usually not be undone. Different types of chemical reaction includes:

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8 0

2 years ago

Please I need this help me

BaLLatris [955]

Answer:

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3 years ago

I need chemistry help! How would I set up these problems?

Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x $10^{11}$ m

Time taken = $\frac{Distance}{Speed}$

= $\frac{1.5 x [tex] 10^{11}$ m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = $\frac{distance}{time}$

= $\frac{63360 inches}{535.2 s}$

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x $10^{-2}$ m

Time taken = 8.92 min

Speed = $\frac{distance}{time}$

= $\frac{63360 x 2.54 x [tex] 10^{-2}$ m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ $\frac{1}{60 hour}$

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

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3 years ago

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xeze [42]

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