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garik1379 [7]
2 years ago
13

Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a

projectile for 1.0 seconds, how fast does the toy car need to be moving as it leaves the ramp?
4.9 m/s
1.0 m/s
9.2 m/s
7.4 m/s m
Physics
1 answer:
jolli1 [7]2 years ago
8 0

Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

v = vy₀/sinθ

v = 4.9/sin32

v = 9.2466...

v = 9.2 m/s

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Robert Oppenheimer made the first atomic bomb.

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Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a
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Answer:

972 J

Explanation:

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GPE = 2.2×9.8×45.08 ≈ 972

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2 years ago
How much elastic potential energy is stored in a bungee cord with a spring constant of 10.0 N/m when the cord is stretched 2.00
Aleonysh [2.5K]

Answer:

<em> The elastic potential energy stored in the bungee cord = 20 J</em>

Explanation:

potential energy: This is the energy possessed by a body due to its position. The S.I unit of energy is Joules. The mathematical expression for elastic potential energy is given below

E = 1/2ke²................ Equation 1

Where E = elastic potential energy of the spring, k = force constant of the spring, e = extension

<em>Given: K = 10 N/m, e = 2.00 m</em>

<em>Substituting these values into Equation 1</em>

<em>E = 1/2(10)(2)²</em>

<em>E = 5×4</em>

<em>E = 20 Joules.</em>

<em>Therefore the elastic potential energy stored in the bungee cord = 20 J</em>

<em></em>

6 0
3 years ago
Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as h
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Answer:

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So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle

As we know that arc length is given as

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length of chord is given as

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6 0
2 years ago
During the deceleration of an ascending elevator, the normal force on the feet of a passenger is _____ her weight. During the de
gizmo_the_mogwai [7]

Answer: Smaller than ; larger than

Explanation:

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When the elevator is moving downward , then the force acting will be positive in nature

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here ma will be positive so it feels larger the original weight of passenger.

7 0
2 years ago
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