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irakobra [83]
3 years ago
10

Write two different subtraction equations that have 7 as the solution ​

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

10-3+7 9-2+7

Step-by-step explanation:

logic this is brain needs

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Passes through the points (−4, 2) and (12, 6)?
svlad2 [7]

<u>I'll assume you need to find the equation of the line that passes through those points.</u>

Answer:

\displaystyle y-2=\frac{1}{4}(x+4)

Step-by-step explanation:

<u>Equation of a Line:</u>

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The given points are (-4,2) and (12,6), thus:

\displaystyle y-2=\frac{6-2}{12+4}(x+4)

Operating:

\displaystyle y-2=\frac{4}{16}(x+4)

Simplifying, the equation in point-slope form is:

\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}

3 0
2 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

Owl= 62.14 + 5

Owl= 67.14ft

7 0
2 years ago
Guys, I'm not sure if I got it right can anyone check it?
Mnenie [13.5K]

Answer: Id say B

Step-by-step explanation:

7 0
3 years ago
Is anyone good with this? I need help finding the answer.
scoray [572]

Answer:

parallel:

7x - 8y = 60

perpendicular:

8x + 7y = 4

Step-by-step explanation:

original line:

-7x + 8y = 4

m = 7/8

parallel:

m = 7/8

L: 7x - 8y = k

(4, -4) -> L

28 + 32 = 60 = k

L: 7x - 8y = 60

perpendicular:

m = -8/7

L: -8x + 7y = k

(4, -4) -> L

-32 + 28 = -4 = k

L: -8x -7y = -4

=> 8x + 7y = 4

7 0
3 years ago
What is the area of this triangle? A=bh2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and
vichka [17]

Answer:

30 m²

Step-by-step explanation:

What is the area of this triangle? A=bh/2 17 m² 30 m² 60 m² 120 m² Right triangle with height labeled 12 m, base labeled 5 m, and third side labeled 13 m.

Area of a triangle = bh/2

b = Base = 5m

h = Height = 12m

Area of the triangle = 5m × 12m/2

= 60m²/2

= 30 m²

6 0
2 years ago
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