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irakobra [83]
3 years ago
10

Write two different subtraction equations that have 7 as the solution ​

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

10-3+7 9-2+7

Step-by-step explanation:

logic this is brain needs

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What is the measure of m? 6 3 n 18 m = [?] Give your answer in simplest form. Enter​
alina1380 [7]

By solving a system of equations, we will see that m measures 12 units.

<h3>How to get the measure of m?</h3>

Notice that we have 3 right triangles.

Then we can write the equations:

cos(a) = 6/m

For the small triangle on the left, where m is the hypotenuse.

cos(a) = m/(6 + 18)

For the larger triangle (the one composed of the two triangles).

Where in both equations, angle "a" is the one in the top left.

Then we have the system of equations:

cos(a) = 6/m

cos(a) = m/(6 + 18)

Then we can write:

6/m = m/(6 + 18)

If we simplify the expression, we get:

6*(6 + 18) = m^2

6*(24) = m^2

144 = m^2

√144 = m = 12

Then we conclude that m measures 12 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

8 0
2 years ago
Determine if each pair or ratio or rate is equivalent. 16 out of 28 and 240 of 560
Keith_Richards [23]

Those ratios are not equivalent because 240 divided by 16 is 15 and 560 divided by 28 is 20.

5 0
3 years ago
Let x denote the courtship time for a randomly selected female–male pair of mating scorpion flies (time from the beginning of in
gavmur [86]

Complete Question:

a) Is it plausible that X is normally distributed?

b) For a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 100 min and 125 min?

Answer:

a) It is plausible that X is normally distributed

b) probability that the sample mean courtship time is between 100 min and 125 min is 0.5269

Step-by-step explanation:

a)X denotes the courtship time for the scorpion flies which indicates that is a real - valued random variable, and since normal distribution is a continuous probability distribution for a real valued random variable, it is plausible that X is normally distributed.

b) Probability that the sample mean courtship time is between 100 min and 125 min

\mu = 120\\n = 50

P(x_{1}  < \bar{X} < x_{2} ) = P(z_{2}  < \frac{x_{2}- \mu }{SD} ) - P(z_{1}  < \frac{x_{2}- \mu }{SD})

SD = \sqrt{\frac{\sigma^{2} }{n} } \\SD = \sqrt{\frac{110^{2} }{50} } \\SD = 15.56

P(100 < \bar{X}

From the probability distribution table:

P(z_{2}  < 0.32 ) = 0.6255\\ P(z_{1}  < -1.29) = 0.0986

P(100 < \bar{X}

6 0
3 years ago
If you need more than 60% of the students surveyed to like your product how many out of 500 would you have to survey
Mashutka [201]
Here is your answer.

6 0
3 years ago
Mpuy each expression.<br> 1) (5p2 – 3) + (2p2 – 3p3)
laila [671]
The anwser is 5x-3 because you remove the parentheses and pair like terms
3 0
3 years ago
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