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dezoksy [38]
4 years ago
9

A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to

brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?
Physics
1 answer:
Mekhanik [1.2K]4 years ago
4 0

Answer:

we have to measure distances and time, possibly with an automated system since the values ​​are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

        I = ∫ F dt = Δp

        F t = m v_{f} - mv₀

In the exercise they indicate that the final speed is zero

         F t = - m v₀

         F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values ​​are very small

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Explain the following behaviour of molecules water rises up in a harrow tubes but mercury which is also a liquid falls in a narr
Mandarinka [93]

Answer: find the answer in the explanation

Explanation:

The capillarity of water molecules is different from the mercury molecules.

What is capillarity ?

This is the tendency of a liquid substance to rise in a capillary tube.

Molecules water rises up in a harrow tubes because of the force of adhesion between the water molecules and the tube molecules is greater than the force of cohesion between the water molecules. This helps water to wet the tube and rise. While mercury which is also a liquid falls in a narrow tubes to level below the outside surface because the force of cohesion between the mercury molecules is greater than the force of adhesion between the mercury molecules and the tube molecules. Mercury does not wet.

7 0
4 years ago
In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
Tcecarenko [31]

Answer:

The amount of heat transfer is 21,000J .

Explanation:

The equation form of thermodynamics is,

ΔQ=ΔU+W

Here, ΔQ is the heat transferred, ΔU is the change in internal energy, and W is the work done.

Substitute 0 J for W and 0 J for ΔU

ΔQ = 0J+0J

ΔQ = 0J

The change in internal energy is equal to zero because the temperature changes of the house didn’t change. The work done is zero because the volume did not change

The heat transfer is,

ΔQ=Q  (in ) −Q (out )

Substitute 19000 J + 2000 J for Q(in)  and 0 J for Q(out)

ΔQ=(19000J+2000J)−(0J)

=21,000J

​Thus, the amount of heat transfer is 21,000J .

​

8 0
3 years ago
Read 2 more answers
If for every action force an equal and opposite reaction force exlsts, how can anything ever be accelerated?
klasskru [66]

Answer:

B

Explanation:

The net force is the force between action and reaction and when this forces are not the same an acceleration is spurred.

3 0
3 years ago
A hammer strikes one end of a thick iron rail of length 8.80 m. A microphone located at the opposite end of the rail detects two
stepladder [879]

Answer:

ΔT = 0.02412 s

Explanation:

We will simply calculate the time for both the waves to travel through rail distance.

FOR THE TRAVELING THROUGH RAIL:

T_{rail} = \frac{Distance}{Speed\ of\ Sound\ in\ Rail}\\\\T_{rail} = \frac{8.8\ m}{5950\ m/s}\\\\T_{rail} = 0.00148\ s

FOR THE WAVE TRAVELING THROUGH AIR:

T_{air} = \frac{Distance}{Speed\ of\ Sound\ in\ Air}\\\\T_{air} = \frac{8.8\ m}{343\ m/s}\\\\T_{air} = 0.0256\ s

The separation in time between two pulses can now be given as follows:

\Delta T = T_{air}-T_{rail} \\\Delta T = 0.0256\ s - 0.00148\ s\\

<u>ΔT = 0.02412 s</u>

3 0
3 years ago
A force F of magnitude 2x^3 is applied to stop a particle moving with an initial velocity of v0. The particle travels from x=0 t
3241004551 [841]

Answer:

Explanation:

Given that

F=2x³

Work is given as

The range of x is from x=0 to x=D

W=-∫f(x)dx

Then,

W=-∫2x³dx from x=0 to x=D

W=- 2x⁴/4 from x=0 to x=D

W=-2(D⁴/4-0/4)

W=-D⁴/2

W=1/2D⁴

The correct answer is F

5 0
3 years ago
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