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dezoksy [38]
4 years ago
9

A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to

brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?
Physics
1 answer:
Mekhanik [1.2K]4 years ago
4 0

Answer:

we have to measure distances and time, possibly with an automated system since the values ​​are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

        I = ∫ F dt = Δp

        F t = m v_{f} - mv₀

In the exercise they indicate that the final speed is zero

         F t = - m v₀

         F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values ​​are very small

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A rod (length = 2.0 m) is uniformly charged and has a total charge of 5.0 nC. What is the electric potential (relative to zero a
Ksenya-84 [330]

Answer:

The electric potential is  V  =  15.6 V

Explanation:

From the question we are told that

   The length  of the rod is  L =  2.0 \ m

     The total charge of the rod is  q =5.0 nC = 5.0*10^{-9} C

      The length from the center is  d =  3.0 \ m

The diagram illustrating the setup for this question is shown on the first uploaded image

From the diagram the potential at point  A  dl is mathematically represented as

         dV  =  K  \frac{dq}{l}

Where K is the coulomb constant with a value  K  = 9*10^9 \   Nm^2 /C^2

where q is the charge in charge  the rod relative to its distance from A  is mathematically represented as

         dq =  \frac{q}{L}  dl

This a small unit length of the rod

So         V = \frac{q}{L}  \int\limits^4_2  {\frac{dl}{l} } \,

        =>   V =  k\frac{q}{L}  ln [\frac{4}{2} ]

              V =  k\frac{q}{L}  ln2

Substituting values

                V  =  9* 10^9  *  \frac{5*10^{-9}}{2} * ln 2

                 V  =  15.6 V

         

7 0
4 years ago
In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an in
Strike441 [17]

Answer:

μs = 0.75

μk = 0.58

Explanation:

From a force diagram:

m*g*sin \theta - Ff=m*a     (1)

N-m*g*cos \theta = 0         (2)

When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):

m*g*sin \theta - \mu*m*g*cos \theta=0   Solving for μs:

\mu=tan \theta

μs = tan 36.7° = 0.75

When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:

μk = tan 30.1° = 0.58

8 0
4 years ago
What is the dimension of resistivity​
Alexandra [31]

Answer:

Are you looking for the formula? because if so:

M L^2 T^-3 I^-2

Explanation:

May I have brainliest please? :)

3 0
3 years ago
If you are driving your car at 45.0 miles per hour, and you have been driving 2.50 hours, how far has your car gone?
Greeley [361]

Answer:

113 miles

Explanation:

45.00 x 2.50= 1.12.5 so 113 miles in 2.50 hours

5 0
3 years ago
Please help on this one!!
inysia [295]

The energy transformations that occur as you coast down long hill on a bicycle, including the brakes to make the bike stop at the bottom, is that at the top of the hill you have high GPE AND LOW KE, on your way down you have HIGH KE AND LOW GPE, and at the bottom you have thermal energy due to the stop of the brakes.

the law of conversation of energy and describe the energy transformations that occur as you coast down a long hill on a bicycle and then apply the brakes to make the bike stop at the bottom.


3 0
3 years ago
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