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Vanyuwa [196]
3 years ago
15

1.) Starting from rest, a car accelerates at 6.52 m/s^2 for 3.80 s. Determine the distance traveled by the car during this time.

Physics
1 answer:
inysia [295]3 years ago
3 0

Answer:

47.1 m

Explanation:

First, write the information you're given.

v₀ = 0 m/s

a = 6.52 m/s²

t = 3.80 s

Identify the variable you're looking for:

Find: Δx

Next, find the kinematic equation you need to solve.  One trick is to identify which variable you <em>don't</em> have, then find the equation that doesn't use that variable.  In this case, we don't have the final velocity v, so the equation we should use is:

Δx = v₀ t + ½ at²

Plug in the values and solve:

Δx = (0 m/s) (3.80 s) + ½ (6.52 m/s²) (3.80 s)²

Δx = 47.1 m

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A mixture of helium and oxygen is used in scuba diving tanks to help prevent ""the bends"". 46 L helium and 12 L oxygen are comb
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Answer

given,

For helium

Volume,V = 46 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₁ = ?

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we know

P V = n R T

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For oxygen

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Pressure,P = 1 atm

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n₂ = ?

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we know

P V = n R T

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P_1=\dfrac{n_1 R T}{V}

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P_2=\dfrac{n_2 R T}{V}

P_2=\dfrac{0.49\times 0.0821\times 298}{5}

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total pressure

    P = P₁ + P₂

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Answer:

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