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Vanyuwa [196]
2 years ago
15

1.) Starting from rest, a car accelerates at 6.52 m/s^2 for 3.80 s. Determine the distance traveled by the car during this time.

Physics
1 answer:
inysia [295]2 years ago
3 0

Answer:

47.1 m

Explanation:

First, write the information you're given.

v₀ = 0 m/s

a = 6.52 m/s²

t = 3.80 s

Identify the variable you're looking for:

Find: Δx

Next, find the kinematic equation you need to solve.  One trick is to identify which variable you <em>don't</em> have, then find the equation that doesn't use that variable.  In this case, we don't have the final velocity v, so the equation we should use is:

Δx = v₀ t + ½ at²

Plug in the values and solve:

Δx = (0 m/s) (3.80 s) + ½ (6.52 m/s²) (3.80 s)²

Δx = 47.1 m

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Alkali metals are in group 1 of the Periodic table which means that they have only a single valence electron.

This causes them to be soft and highly reactive because:

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