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katen-ka-za [31]
3 years ago
13

Choose an organism that you are familiar with, and explain how the three parts of the cell theory relate to the organism

Chemistry
2 answers:
jek_recluse [69]3 years ago
6 0
Organism: Apple
All cells from the apple come from cell division occurring from the apple in order for it to grow. 
An apple has multiple cells
The small living part in an apple is a cell thus showing that cells are the basic living unit.
natta225 [31]3 years ago
6 0

Answer:

Organism: Chicken

Explanation:

Let's suppose we have a chicken.

Chicken is a multicellular organism, with several parts such as wings, legs among many others.

The first part of cell theory: All organisms are made of one or more cells. Chicken is composed of several cells, cells are a couple in organs, such as hearth, legs and other. Each organ is composed of a specialized type of cell.

The second part of cell theory: The cell is the basic unit of organisms.The cell is the minimum expression of living organisms. Cells can eat, drink, digest and breath. Due to it, cells are the basic unit of organisms. Each cell inside the chicken can achieve own functions by itself.

Third. All cells come from existing cells.If we analyze the chicken origin, we can notice that chicken life began as an egg, a single giant cell. With time going, the single cell of the chicken was reproducing until it reaches the organism and many cells. In this sense, all chicken cells come from a single existing cell of the egg. 

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Using a molar heat of combustion of hexane (C6H14) –4163 kJ/mol, the mass of hexane required to increase the temperature of 1.76
pshichka [43]

Answer:

7.46 g.

Explanation:

  • Firstly, we need to calculate the amount of heat needed to warm 5.64 kg of water from 21.0°C to 70.0°C using the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by water (Q = ??? J).

m is the mass of water <u><em>(m: we will determine).</em></u>

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  70.0 °C - 21.0 °C = 49.0 °C).

  • To determine the mass of 1.76 L of water we can use the relation:

mass = density x volume.

density of water = 1000 g/L & V = 1.76 L.

∴ mass = density x volume = (1000 g/L)(1.76 L) = 1760.0 g.

∵ Q = m.c.ΔT

<em>∴ Q = m.c.ΔT </em>= (1760.0 g)(4.186 J/g.°C)(49.0 °C) = 360483.2 J ≅ 360.4832 kJ.

  • As mentioned in the problem the molar heat of combustion of hexane is - 4163.0 kJ/mol.

<em>Using cross multiplication we can get the no. of moles of hexane that are needed to be burned to release 360.4832 kJ:</em>

Combustion of 1.0 mole of methane releases → - 4163.0 kJ.

Combustion of ??? mole of methane releases → - 360.4832 kJ.

∴ The no. of moles of hexane that are needed to be burned to release 360.4832 kJ = (- 360.4832 kJ)(1.0 mol)/(- 4163.0 kJ) = 0.0866 mol.

  • Now, we can get the mass of hexane that must be burned to warm 1.76 L of water from 21.0°C to 70.0°C:

<em>∴ mass = (no. of moles needed)(molar mass of hexane)</em> = (0.0866 mol)(86.18  g/mol) = <em>7.46 g.</em>

5 0
3 years ago
Which of the following values displays the pH of a base?
gayaneshka [121]

Answer:

9 is your answer

Explanation:

coz anything above 7.0 is Base on PH paper !

Hope you got it.

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A scientist is creating a new synthetic material. The material’s density is 6.1 g/cm3. Which sentences describe how the scientis
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Helppp ! Please :’)
Over [174]

Answer:

\boxed{\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm}

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

\frac{1}{ \lambda}  = R_H {Z}^{2}  \big(\frac{1}{{n_f^2}}  - \frac{1}{{n_i^2}} \big)

Where,

  • λ is wavelength of photon
  • Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in <em>Puri Sharma Pathania</em> standard book of physical chemistry &

109737 Cm-¹ according to <em>Wikipedia</em>

  • Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{3^2}}  - \frac{1}{{5^2}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{9}}  - \frac{1}{{25}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{25 - 9}{25 \times 9}

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{16}{225}

\frac{1}{ \lambda}  =   7800.18 \: \: cm ^{ - 1}

\lambda = 1.282 \times  {10}^{ - 4} cm

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

\lambda \:  = 1.282 \times  {10}^{ - 4} \times  {10}^{7}

\lambda \:  = 1.282 \times  {10}^{ - 4 + 7}

\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm

\sf \small Thanks \:  for \:  joining \:  brainly  \: community!

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3 years ago
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