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laila [671]
3 years ago
5

Why is measuring the size of an atom difficult

Chemistry
1 answer:
vlada-n [284]3 years ago
5 0
<span>Atomic size is the distance from the nucleus to the valence shell where the valence electrons are located. Atomic size is difficult to measure because it has no definite boundary. The electrons surrounding the nucleus exist in an electron cloud.
</span>
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The reaction described in Part A required 3.54 L of magnesium chloride. What is the concentration of this magnesium chloride sol
labwork [276]

we need the cholride solution Part B to answer your question

7 0
3 years ago
Which balanced equation represents a redox reaction? a. AgNO3(aq) +NaCl(aq) →AgCl(s) +NaNO3(aq) b. H2CO3(aq) →H2O() + CO2(g) c.
Aleks [24]

Answer : The correct option is, (D) Mg(s)+2HCl(aq)\rightarrow MgCl_2(s)+H_2(g)

Explanation :

(A) AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)

This reaction is a double displacement reaction in which the cation and anion of two reactants are exchange their places to give two different products.

(B) H_2CO_3(aq)\rightarrow H_2O(l)+CO_2(g)

This reaction is a decomposition reaction in which the larger molecule decomposes to give two or more products.

(C) NaOH(aq)+HCl(aq)\rightarrow NaCl(s)+H_2O(aq)

This reaction is a neutralization reaction in which an acid and a base react to give a salt and water as a product.

(D) Mg(s)+2HCl(aq)\rightarrow MgCl_2(s)+H_2(g)

This reaction is a redox reaction in which the oxidation and reduction reaction occur simultaneously.

Oxidation reaction is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction is the reaction in which a substance gains electrons. In this oxidation state decreases.

In this reaction, magnesium shows oxidation due to change in oxidation number from (0) to (+2) and hydrogen shows reduction due to change in oxidation number from (-1) to (0).

Hence, the correct option is, (D)

7 0
3 years ago
How many moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5L
mihalych1998 [28]

Multiply the values.

n = cv

Where

n =mol

c = concentration

v = volume

n = 2.5×1.5 = 3.75mol

3 0
3 years ago
Be sure to answer all parts. Hydrogen iodide decomposes according to the reaction 2 HI(g) ⇌ H2(g) + I2(g) A sealed 1.50−L contai
Zarrin [17]

Answer : The concentration of HI and I_2 at equilibrium is, 0.0158 M and 0.00302 M respectively.

Explanation :

First we have to calculate the concentration of H_2, I_2\text{ and }HI

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.00623mol}{1.50L}=0.00415M

\text{Concentration of }I_2=\frac{\text{Moles of }I_2}{\text{Volume of solution}}=\frac{0.00414mol}{1.50L}=0.00276M

\text{Concentration of }HI=\frac{\text{Moles of }HI}{\text{Volume of solution}}=\frac{0.0244mol}{1.50L}=0.0163M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

                            2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initial conc.      0.0163     0.00415      0.00276

At eqm.        (0.0163-2x) (0.00415+x)  (0.00276+x)

As we are given:

Concentration of H_2 at equilibrium = 0.00467 M

That means,

(0.00415+x) = 0.00467

x = 0.00026 M

Concentration of HI at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M

Concentration of I_2 at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M

8 0
4 years ago
A 65.0-mL aqueous solution contains 7.54 g of copper (II) chloride, CuCl2. Calculate the molarity of the solution. {Ans. ~ [CuCl
Kamila [148]

The first thing we need to remember is that:

We have 7.54g of CuCl2 so we need to express this amount in moles dividing by the molar mass of CuCl2.

This is:

And, also remember that 65.0mL equals 0.065L.

Now, replacing in the molarity equation:

Thus the answer is 0.862M.

6 0
1 year ago
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