Answer:
285 Litre ( 1kg of water occupies 1 Litre )
which is identical to 285 dm^3 ie 285 cubes of length 10 cm
and as there are 10 of these linearly in 1 m then there are 10^3 = 1000 dm^3 in each m^3
giving a volume of 0.285 m^3
Of course if you KNEW that 1m^3 of water has a mass of 1000 kg then you would simply have said that the volume was 285/1000 m^3
<h2>K.E/P.E = m/k tan²φ x ω²</h2>
Explanation:
The given position of block x = x₀ cos(ωt + φ)
The velocity of block v = dx/dt = - x₀ sin(ωt + φ) x ω
The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²
The potential energy of spring = 1/2 k x² , where k is the spring constant
Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)
When t = 0
K.E = 1/2 m x₀²sin²φ x ω²
P.E = 1/2 k x₀² cos²φ
Dividing these , we have
K.E/P.E = m/k tan²φ x ω²
Answer:
B. T
Explanation:
This is because the mass of the Bob does no relate to the period as given by the relationship
T = 2π(√L/g) so double mass is still T
This is what i found idk if its right or not so yeahhhhhh.
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