Answer:
Explanation:
In the following reaction we have shown an example of aromatic substitution reaction .
C₆H₆ + RCl = C₆H₅R + HCl
This reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .
First of all formation of carbocation is made as follows .
RCl + AlCl₃ = R⁺ + AlCl₄⁻
This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .
C₆H₆ + R⁺ = C₆H₅R⁺H.
The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .
C₆H₅R⁺H + AlCl₄⁻ = C₆H₆ + AlCl₃ + HCl .
The formation of a stable product C₆H₆ also drives the reaction to form this product .
Workplace Hazardous Materials Information System is the answer to this question. Hope it helps :)
Answer:
The value is 
Explanation:
From the question
The equation given is
NiO(s) + H2(g) ⇌ Ni(s) + H2O(g) Kc=40 (1)
NiO(s) +CO(g) ⇌ Ni(s) +CO2(g) Kc=600 (2)
Generally the reverse of the second equation as shown below
Ni(s) +CO2(g) ⇌ NiO(s) + CO(g) (3)
The equilibrium constant becomes 
Now adding 1 and 3 we obtain
NiO(s) + H2(g)+ Ni(s) +CO2(g) ⇌ Ni(s) + H2O(g)+NiO(s) + CO(g)
CO2(g) + H2(g) ⇌ CO(g) + H2O(g)
Hence the equilibrium constant for the resulting equation is mathematically evaluated as
=> 
=>
Answer:
197 grams
Explanation:
Without taking into account the number of sig figs you have for your values, you can say that the answer will once again be
197 g of aluminium bromide.
(I hope this is right)
