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Arte-miy333 [17]
2 years ago
14

Describe the concentration of hydronium ions and hydroxide ions when a base is added slowly to a white vinegar solution. The pH

of white vinegar is 3.1. Explain
Chemistry
1 answer:
aalyn [17]2 years ago
7 0

Answer:as you add the base it added some  PH. The Ph lever of white winegaer is2.4 - 3.4

Explanation:

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Write a net ionic equation for the reaction between mno4- and fe2+ in acid solution
dedylja [7]
Answer : The complete net ionic reaction between MnO _{4}  ^{-} and Fe ^{2+} in an acid solution, can be written as :-

MnO _{4}  ^{-}  + 5Fe ^{2+} + 8 H ^{+} ----\ \textgreater \  Mn ^{2+} + 5 Fe^{3+} + 4 H _{2}O.
6 0
3 years ago
How many ions are in 1.50 grams of Na+?
Jobisdone [24]

Answer:

= 0.0652 moles

Explanation:

I hope it helps you

7 0
2 years ago
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit
ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 10.28g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell =?

Putting values in above equation, we get:

10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm

Conversion factor used:  1cm=10^{10}pm  

Hence, the edge length of the unit cell is 314 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 314}{4}=135.9pm

Hence, the radius of the molybdenum atom is 135.9 pm

4 0
3 years ago
What is the molality of a solution of 10 g NaOH in 500 g water?<br>Molar mass NaOH = 40 g​
umka2103 [35]

Explanation:

Moles of NaOH = 10g / (40g/mol) = 0.25mol.

0.25mol / 500g = 0.50mol / 1000g = 0.50mol/dm³.

The molarity is 0.50mol/dm³.

4 0
3 years ago
HELP ASAP
Bezzdna [24]
A. I think sorry if it’s wrong
5 0
3 years ago
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