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34kurt
3 years ago
10

Which of the following is true? Group of answer choices worst case time of Heapsort is better than worst cast time of Quicksort

average case time of Quicksort is better than average case time of Heapsort best case time of Quicksort is worse that best case time of Heapsort both a) and b)
Computers and Technology
1 answer:
Sav [38]3 years ago
8 0

Answer:

Worst case time of Heapsort is better than worst case time of Quicksort.

Explanation:

Worstcase of Heapsort is nlog(n). Worstcase time of Quicksort is (n^2). Heapsort is comparison based sorting algorithm. Heapsort divides input into sorting. It is a selection sort in which we send maximum inputs for maximum elements at end. Quicksort is divide and conquer algorithm. It is considered as efficient sourcing algorithm.

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Read 2 more answers
C++
Nookie1986 [14]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

class Window //defining a class Window

{

private:

int width, height;//defining integer variable

public:

friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters

{

return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values

}  

Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters  

{}

};

int main() //Main method

{

Window w(80,90);//calling class constructor

cout<<w;//print object value

return 0;

}

Output:

a (80 x 90) window

Explanation:

In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.

Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.

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Answer:

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CLS

INPUT “ENTER ANY NUMBER”; N

CALL SQUARE(N)

END

SUB SQUARE (N)

S = N ^ 2

PRINT “SQUARE OF NUMBER “; S

END SUB

3 0
3 years ago
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