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AlexFokin [52]
3 years ago
14

What is the resistance of a 4.4-m length of copper wire 1.5 mm in diameter? The resistivity of copper is 1.68×10−8Ω⋅m.

Physics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

R = 4.18 * 10^8ohms

Explanation:

R=resistance in ohms=?

ρ=resistivity of material in ohms meters = 1.68*10^-8 oh ohm meters

L= length of the object (m) = 4.4m

A = cross-sectional area of the object in square meters (m^2)= πr^2

r = (1.5mm/1000)/2= 0.00075m

A=π*(0.00075)^2 = 1.76714586764426*10^-6

Approximately, A = 1.767m^2

R = ρL/A= (1.68*10^8Ω⋅m) * (4.4m)/(1.767m^2)

R = 418336162.988115 ohms

Approximately, R = 4.18 * 10^8ohms.

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Explanation:

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If you have 3 equal plates hanging 2 spaces from the center of a balance, at what distance would you need to place 2 equal plate
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You answere would be C. 3 spaces
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two clear, colorless liquids are poured together. A bright yellow solid forms. What physical properties have changed?
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A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 10° F. Af
vekshin1

Answer:

T=51.64^\circ F

t=180.10s

Explanation:

The Newton's law in this case is:

T(t)=T_m+Ce^{kt}

Here, T_m is the air temperture, C and k are constants.

We have

70^\circ F in t=0

So:

T(0)=70^\circ F\\T(0)=10^\circ F+Ce^{k(0)}\\70^\circ F=10^\circ F+C\\C=70^\circ F-10^\circ F=60^\circ F

And we have 60^\circ F in t=30 s, So:

T(30)=60^\circ F\\T(30)=10^\circ F+(60^\circ F)e^{k(30)}\\60^\circ F=10^\circ F+(60^\circ F)e^{k(30)}\\50^\circ F=(60^\circ F)e^{k(30)}\\e^{k(30)}=\frac{50^\circ F}{60^\circ F}\\(30)k=ln(\frac{50}{60})\\k=\frac{ln(\frac{50}{60})}{30}=-0.0061

Now, we have:

T=10^\circ F+(60^\circ F)e^{-0.0061t}(1)

Applying (1) for t=1 min=60s:

T=10^\circ F+(60^\circ F)e^{-0.0061*60}\\T=10^\circ F+(60^\circ F)0.694\\T=10^\circ F+41.64^\circ F\\T=51.64^\circ F

Applying (1) for T=30^\circ F:

30^\circ F=10^\circ F+(60^\circ F)e^{-0.0061t}\\30^\circ F-10^\circ F=(60^\circ F)e^{-0.0061t}\\-0.0061t=ln(\frac{20}{60})\\t=\frac{ln(\frac{20}{60})}{-0.0061}=180.10s

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What are the forces like in a collision?
Anuta_ua [19.1K]

Answer:

The forces are a convergent

Explanation:

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