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3 years ago

How do you calculate bonding capacity in chemistry?

Chemistry

1 answer:

Anna [14]3 years ago

3 0

Answer:

bonding capacity is based on the oxidation number. the pattern throughout families 1-2 and 13-18 is 12343210. depending on wether the elements in a family lose or gain 1-4 valence electrons is what determines the bonding capacity. for example, the elements in family one, or the Alkali family elements, lose one valence electron to become stable. this means the next outer shell has 8 valence electrons and is therefore stable. family two elements lose 2 valence electrons in order to have 8 on the outer shell. family thirteen elements lose 3 valence electrons. family fourteen can either lose or gain their four valence electrons as long as they end up with an outer shell with 8 valence electrons. family fifteen gains 3 valence electrons, 16 gains two, and 17 gains 1. family 18 doesn't lose or gain any since it is already stable. if an element loses valence electrons its oxidation number will be a positive 1,2,3, or 4. if an element gains valence electrons its oxication number will be a negative 1,2,3, or 4. the pattern of oxidation numbers is the same as the bonding capacity and it is +1,+2,+3,+4/-4,-3,-2,-1 or 0. basically if you can find the oxidation number then you can find the bonding capacity

Explanation:

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How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol

mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

$2Al + 3Cu{(NO_3)}_2 \rightarrow 2Al{(NO_3)}_3 +3 Cu$

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

$Al \rightarrow Al^{3+} + 3e^-$

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On balancing the number of electrons we get:

For 1 mole of Al $6e^-$ is required.

Therefore for 2 moles of Al,

Total $(2\times6)$ F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

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Explanation:

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