Nonmetallic binds are commonly
<span>The balanced chemical equation for this reaction is:
2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)
According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.
The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)
mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4
As per the equation, the number of moles of NaOH used is:
0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH
Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :
Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M
Therefore, the concentration of NaOH is 0.67 M.</span>
Concentration of hydrogen ions remaining in the final solution is 
In original solution we have 1.450M of HCl
1.450 M means 1.450 moles of HCl in 1 liter of water
Therefore, number of moles of HCl in 500ml of water will be
=
moles
= 0.725 moles of HCl
Reaction between HCl and Zn happens when zinc is added -
→ 
Therefore two moles of HCl is needed for 1 mole of zinc
Thus number of moles of HCl needed to react with 12.7g of Zinc will be
= 
= .388 Moles
So moles of HCl left =
= 0.3365 moles
In 1 Mole of HCl there is 1 mole of H because
→ 
Therefore in 0.3365 mole HCl there will be 0.3365 moles of H
Thus final concentration of H ions in final solution is =
= 
= 0.673M
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Answer:
The correct option is D
Explanation:
Normally, beta-oxidation of fatty acid occurs in the mitchondrial matrix, however, when the fatty acid chains are too long, the beta-oxidation occurs in the peroxisomes <u>where the oxidation is not attached to ATP synthesis but rather transferred (i.e high energy electrons are transferred) to O₂ to form hydrogen peroxide</u> (H₂O₂). This is the major difference between the beta-oxidation that occurs in the peroxisomes to that which occurs in the mitochondria.