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1 year ago

(b) Do compounds of hydrogen exhibit a relatively large or small kinetic isotope effect? Explain.

Chemistry

1 answer:

joja [24]1 year ago

6 0

Compounds of hydrogen exhibit a relatively large kinetic isotope effect.

The phenomenon known as the kinetic isotope effect (KIE) is brought on by the variable reaction speeds that are displayed by isotopically substituted compounds. When it comes to studying reaction kinetics, mechanisms, and solvent effects, isotope effects like KIEs are invaluable tools in both physical and biological sciences. The replacement of hydrogen with deuterium is a highly frequent isotope substitution. The ratio kH/kD, which describes this as a "deuterium effect," is used to measure it. Due to the proportion, significant effects are observed.

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2 years ago

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GarryVolchara [31]

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explaiation:-

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3 years ago

A solution of sugar contains 35 gramsof sucrose, C12H22O11in 100 mL of water. What is the percent composition of the solution?

KATRIN_1 [288]

Answer:

Percent composition of the solution is 26 % of sucrose and 74 % of water

Explanation:

Percent composition is the mass of solute, either of solvent in 100 g of solution.

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Mass of solute = 35 g

Mass of solvent = 100 g

As we know, water density = 1g/mL

So 1g/mL . 100 mL = 100 g

35 g + 100 g = 135 g → Mass of solution

(Mass of solute / Mass of solution) . 100 =

(35 g / 135 g) . 100 = 26 %

(Mass of solvent / Mass of solution) . 100 =

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8 0

2 years ago

NaCl + H2SO4 ---> Na2SO4 + HCl Balance the double replacement chemical reaction.

VikaD [51]

Answer:

2NaCl+H2SO4-->Na2SO4+2HCl

Explanation:

There are two Na on the right, so put a 2 in front of NaCl on the left. This makes 3 Cl also, so put a 2 in front of HCl on the right. There are already 2 H on the left, so the equation is balanced.

7 0

3 years ago

A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?

DedPeter [7]

Answer:

2.99 M

Explanation:

In order to solve this problem we need to keep in mind the definition of molarity:

Molarity = moles of solute / liters of solution

In order to calculate the moles of solute, we convert 125.6 g of NaF into moles using its molar mass:

125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF

As the volume is already given, we can proceed to calculate the molarity:

Molarity = 2.99 mol / 1.00 L = 2.99 M

4 0

2 years ago